Latest TCS Aptitude Question SOLUTION: What is the remainder when 121212......(300 digits) is divided by 99?

• Placement Papers
• /
• TCS

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40028855) TCS question Keep an EYE

What is the remainder when 121212......(300 digits) is divided by 99?

Asked In TCS (10 years ago)

Unsolved Read Solution (14)

Is this Puzzle helpful?   (5)   (3) Submit Your Solution

Read Solution (14) :

Prokriti Chatterjee  (10 years ago)

12/99 gives rem= 12
1212/99 gives rem= 24 (12*2)
121212/99 gives rem= 36 (12*3)
similarly,for 300 digits we have 150 12's
therefore,12121212....300 digits/99 gives rem =150*12=1800
Now 1800/99 gives rem =18.
thus ans=18.

Is this solution Helpfull? Yes (52) | No (6)  

aditi jain  (10 years ago)

18 will be the remainder

Is this solution Helpfull? Yes (5) | No   

RAKESH  (10 years ago)

121212......(300 digits)/(9*11)
sum of 300 digits=3*150=450
so given no. is divisible by 9
thenafter dividend is divided by 11
remainder must be less than 11
all the answers are incorrect
remainer will be 8
when given no. is divied by 9 dividend will be 13468013468...13468(134680 will be 49 times and last five digit 13468),it will divided by 11,48 times of 134680 will be completely divisible,the last 11 digit 13468013468 wll give the required remainer which is 8

Is this solution Helpfull? Yes (4) | No (1)  

vishal marodia  (10 years ago)

12/99=remainder (12*1=12)
1212/99=remainder (12*2=24)
121212/99=remainder (12*3=36)
so 121212.....upto 300 times=remainder(12*300=3600)
3600/99=(99*36)+36
so remainder is (36)

Is this solution Helpfull? Yes (3) | No (4)  

amrtuha  (10 years ago)

when 1800/99 then quotient is 18
and remainder = 2
then how u got rem=18..
plz explain me

Is this solution Helpfull? Yes (3) | No (1)  

gopal singh  (10 years ago)

121/99=1*99+12
121121/99=1223*99+2*12
so 12*300/99=72*99+72.....hnce 72 is requried remainder

Is this solution Helpfull? Yes | No (10)  

ravendra tiwaree  (10 years ago)

reminder will be 8...

Is this solution Helpfull? Yes | No (7)  

samarth shrivastava  (10 years ago)

6 is the remainder.
121212... when divided by (3*3*11)
121212....divided by 3 gives 40404... i.e. remainder 0
divisibility rule of 11 : (sum of digit at even places)- (sum of digits at odd places)= multiple of 11
thus 4+4+4+...150times=600 , not divisible by 11
thus 600=594+6. hence making the no 404040.. as ((404040.......46)-6) and hence getting 6 as the remainder.

Is this solution Helpfull? Yes | No   

SOUMYADIP SAHA  (10 years ago)

12/99 gives rem= 12
1212/99 gives rem= 24 (12*2)
121212/99 gives rem= 36 (12*3)
similarly,for 300 digits we have 150 12's
therefore,12121212....300 digits/99 gives rem =150*12=1800
so ans. is 1800

Is this solution Helpfull? Yes | No   

RAKESH  (10 years ago)

the remainder will be 8*9=72
in the last attempt imade it 8
it willbe 8*9 as already divided by 9

Is this solution Helpfull? Yes | No   

Pradeep   (10 years ago)

Reminder is 9

Is this solution Helpfull? Yes | No   

Rajat Subhra Bhowmick  (10 years ago)

1212......300/3*3*11=
40404.....299/3*11
so answer is less than 33 which is 18

Is this solution Helpfull? Yes | No   

suparna das  (10 years ago)

remainder is 0

Is this solution Helpfull? Yes | No   

Guru Pranav  (10 years ago)

18

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.