Latest CTS Aptitude Question SOLUTION: Given the following functions (1) f(n a b c ) = ac if n=1 (2) f(n a b c) = f( n-1 a c b) + f( 1 a b c) + f( n-1 b a c ) if n > 1 Then what is the value f( 2 a b c ) = ?

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Given the following functions (1) f(n a b c ) = ac if n=1 (2) f(n a b c) = f( n-1 a c b) + f( 1 a b c) + f( n-1 b a c ) if n > 1 Then what is the value f( 2 a b c ) = ?

Asked In CTS chandreyee chowdhury (10 years ago)

Unsolved Read Solution (7)

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RAKESH  (10 years ago)

f(n a b c ) = ac for n=1
f(n a b c) = f( n-1 a c b) + f( 1 a b c) + f( n-1 b a c ) for n > 1
so f( 2 a b c )=f( 2-1 a c b) + f( 1 a b c) + f( 2-1 b a c ) as n=2>1
=f( 1 a c b) + f( 1 a b c) + f( 1 b a c )
(put the values of three term from 1st eqn for n=1)
=ab+ac+bc

Is this solution Helpfull? Yes (80) | No   

Gomathi  (10 years ago)

f( 2 a b c)=ab + bc +ac

Is this solution Helpfull? Yes (5) | No   

mayank gupta  (10 years ago)

the ans is ab+ac+bc

Is this solution Helpfull? Yes (2) | No   

bhargava  (10 years ago)

ans:
ab+bc+ac

Is this solution Helpfull? Yes (2) | No (1)  

hegdeshashanka  (10 years ago)

f(n abc)=f(n-1 acb)+f(1 abc)+f(n-1 bac)
asked is f(2abc) so put n=2 we get f(2abc)=f(1 acb)+ac+f(bac)
so by the funct definition middle term is omitted so f(2abc)=ab+ac+bc

Is this solution Helpfull? Yes (2) | No   

UMAMAHESWARI.P  (10 years ago)

f(2 a b c)=ab+ac+bc
f(1 a c b)=ab
f(1 b a c)=bc

Is this solution Helpfull? Yes (1) | No (2)  

santanu sarma  (10 years ago)

for,f(2abc) = f(2-1abc)+f(1abc)+f(2-1abc)
=f(1abc)+f(1abc)+f(1abc)
=3f(1abc)
=3ac (since, f(nabc)=ac; n=1)

Is this solution Helpfull? Yes | No (7)  

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