Latest TCS Aptitude Question SOLUTION: 1,5,6,25,26,30,31,125,126...........what is the value of 30th term in the given series?

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(#M40029981) TCS Logical Reasoning question Keep an EYE

1,5,6,25,26,30,31,125,126...........what is the value of 30th term in the given series?

Asked In TCS pre (10 years ago)

Unsolved Read Solution (13)

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choton chowhan  (10 years ago)

1st term gives 2nd and 3rd term as 1*5,(1*5)+1
similarly: 2nd trm gives 4th nd 5th term as 5*5,(5*5)+1
3rd term gives 6th nd 7th trm......
...................................
7th term gives 14th nd 15th term as 31*5,(31*5)+1 =155,156
thus 15th term is 156
now similrly 15th term gives 30th and 31th term as 156*5,(156*5)+1
ans. 30th term is 780.

Is this solution Helpfull? Yes (55) | No (2)  

tejomay saha  (10 years ago)

it may be the series that aftr 1 evry term *5 ,*5+1 like the serise is 1 5 6 25 26 30 31 125 126 130 131 10 151 155 156 625 626 .............780 ,30th term=780 .is it right

Is this solution Helpfull? Yes (20) | No (3)  

Utsav Dawn  (10 years ago)

we are getting 2nd term by multiplying 5*1st term, 4th term by 5*2nd term, similarly we will get 30th term by 5*15th term..now we will get 14th term= 5*7th term=5*31=155. so 15th term=14th term+1= 155+1=156. therefore 30th term=5*156=780..

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Abhideep Saha  (10 years ago)

780.. 1*5=5,5+1=6,5*5=25,25+1=26.....31*5=155, 155+1=156 is the 15th term. so 13th term will b= 156*5=780

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Pratyusha Bhadra  (10 years ago)

sorry guys..i was wrong last tym..the answr wl be 780...

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samayeta mondal  (10 years ago)

1,5,6,25,26,30,31,125,126,130,131,625,626,630,631,3125,3126,3130,3131,15625,15626,15630,15631,78125,78126,78130,78131,390625,390626,390630.

Is this solution Helpfull? Yes (1) | No (6)  

prasanjit sarkar  (10 years ago)

I think it will be .......1755 (30th term)

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lavanya  (10 years ago)

How can u explain

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Pratyusha Bhadra  (10 years ago)

answr is 5^8+1+4=390630

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ira upadhyay  (10 years ago)

156*7=780;

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Rakesh Kumar  (10 years ago)

Ans will be 780.
the series is going from starting number is *5 then *5+1.

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jitendra singh  (10 years ago)

i think 136627 is ans

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Nehal Chourey  (10 years ago)

the series started for (1st and 2nd) term is(1, 5) and for (nth, nth+1) terms is (((n-1)th term +1),(5*(n/2)th term)) where n is for odd term, so for 30th term(even term)= 5*((30/2)th)=5*156=780.

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