Latest Oracle Aptitude Question SOLUTION: Q. A charitable woman gave one penny more than half pennies in her purse to a farmer .Afterwards she came across a beggar whom she gave 2 pennies more than half of what she had in

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Q. A charitable woman gave one penny more than half pennies in her purse to a farmer .Afterwards she came across a beggar whom she gave 2 pennies more than half of what she had in her purse. In the end she gave 3 pennies more than half of what she had in her purse and left with a penny with her to a boy. Find what she had in the beginning?

Asked In Oracle chandreyee chowdhury (10 years ago)

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ADARSHS SINHA  (10 years ago)

let there b 'x'pennies

now to the farmer:
she gave 1 penny more than the half in the purse i.e (x/2 +1)

now she is left with:: (x-(x/2+1))=(x-2)/2

now to the beggar::
she gave 2 pennies more than the half in the purse i.e(x-2)/4 +2

and she is left with :: ((x-2)/2)-((x-2)/4 +2)= (x-10)/4


now at last

sh gave 3 pennies more then the half she was left with i.e ((x-10)/8+ 3)=A


so she is left with
(x-10)/4-A=(x-34)/8

now acc. to quest
(x-34)/8=1

hence x=42

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iman  (9 years ago)

At the end she had 1
lets before last donation she had n pennies so n-(n/2)-3 = 1 =>n=8
........before second donation she had m ... m-(m/2)-2 = 8 => m=20
..........before first donation she had p... p-(p/2)-1 = 20=> p=42

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