Latest HCL Aptitude Question SOLUTION: Q. 6 women can do 75 unit of work in 8 days by working 5hr/day in how many days 4 women do 30 units of work by working 8hr/day

• Placement Papers
• /
• HCL
• /
• Numerical Ability
• /
• Time and Work

HCL Question Papers: HCL Interview Experience(1) HCL Company Profile

(#M40031884) HCL Numerical Ability question Keep an EYE

Q. 6 women can do 75 unit of work in 8 days by working 5hr/day in how many days 4 women do 30 units of work by working 8hr/day

Asked In HCL binapani nayak (10 years ago)

Solved MURALI KUDUPUDI Read Solution (11)

Is this Puzzle helpful?   (29)   (2) Submit Your Solution Time and Work

Read Solution (11) :

MURALI KUDUPUDI  (10 years ago)

(6x8x5)/75=(Ax4x8)/30
A=3

Is this solution Helpfull? Yes (47) | No   

PARVY GOVIL  (10 years ago)

use (man*days*hours /work).thus m1*d1*hi /w1 = m2*d2*h2 /w2. hence d2 is 3

Is this solution Helpfull? Yes (17) | No   

Devendra Marghade  (10 years ago)

3 days
6 Women---8*5(=40)DayHour---75 Units
4 Women---8*5 DayHour---75*2/3(=50)Units
4 Women---40(3/5)DayHour---30 Units
4 Women---24 Dayhour---30 Units
So for 30 Units of work,4 Women working 8 hr/day requires 24/8= 3 days

Is this solution Helpfull? Yes (9) | No   

Priyanka Harjai  (10 years ago)

Ans will be 3 days..
Because..
6 Women can complete in 8 days...So,4 Women will complete in more days..(Indirect prorportin)
75 units of work done in 8 days..So,30 unit of work will be done in less days.(Direct prorportion)
Working 5hr/day takes 8 days..So,Working 8hrs/days takes less days(Indirect prorportion )
So, 4*75*8*x=6*30*5*8
x=3 days

Is this solution Helpfull? Yes (4) | No   

Raju  (10 years ago)

6 womwn---75 unit--- 5hr/day = 8 days
1 '' 1 '' 1 '' = 8*6*5/75
4 '' 30 '' 8 '' = (8*6*5*30)/(75*4*8)=3 days

Is this solution Helpfull? Yes (3) | No   

sheetal kothari  (10 years ago)

6*75*5:4*30*8::8:x
now solve this
30*75*x=120*8*8
7680=2250x
x=3

Is this solution Helpfull? Yes (3) | No   

A.P.Singh  (10 years ago)

Total woman hrs reqd. for 75 units of work = 6*8*5=240
woman hrs reqd. for 1 units of work = 240/75
woman hrs reqd. for 40 units of work = 240*40/75 = 128
no of days required = 128/(4*8)= 4 days

Is this solution Helpfull? Yes (2) | No (7)  

Suresh Elluri  (10 years ago)

(6*8*5)/75=(A*4*8)/30
A=3

Is this solution Helpfull? Yes (2) | No   

Neeraj Tripathi  (10 years ago)

trick:
M1D1H1W2=M2D2H2W1
6*8*5*30=4*D2*8*75
SOLVE TH EQUATION ANS=3

Is this solution Helpfull? Yes (2) | No   

krishna  (10 years ago)

8*6/4*30/75*5/8=3

Is this solution Helpfull? Yes (2) | No   

Kottakota bharat  (4 years ago)

m1*d1*h1/w1 = m2*h2*d2/w2 formula substitute get 3

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.