Latest TCS Aptitude Question SOLUTION: Q. How many 9 digit number can be formed from 1,2,3,4,5 which is divisible by 4,repetition is allowed?

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Q. How many 9 digit number can be formed from 1,2,3,4,5 which is divisible by 4,repetition is allowed?

Asked In TCS Divya (10 years ago)

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Read Solution (7) :

RAKESH  (10 years ago)

digits are 1,2,3,4,5
for a no. to be divisible by 4, last two digit should be divisible by 4

last two digit may be 12,24,32,44,52 (5 ways)
last two places can be filled in 5 ways
so, remaining 7 places, each place can be filled in 5 ways => 5^7 ways

total no. formed = 5 * 5^7 = 5^8

Is this solution Helpfull? Yes (54) | No   

roli khattri  (10 years ago)

@rakesh ur genius

Is this solution Helpfull? Yes (15) | No (2)  

shahrukh  (9 years ago)

rakesh bhai hats off

Is this solution Helpfull? Yes (2) | No (2)  

Dharmendra Shukla  (9 years ago)

Ans:
2*5^8
because 8th place can be filled with the digits 1 2 3 4 5 so this can also be filled in 5 ways but the 9th place can be filled in 2 ways because only 2 and 4 comes there hence ans will be 2*(5^8)

Is this solution Helpfull? Yes (1) | No (4)  

ARCHIE GUPTA  (9 years ago)

5^7(3+2)=5^8

Is this solution Helpfull? Yes | No (1)  

pratiksha vishwas  (9 years ago)

as we consider last two digits of the no. to check the divisibility by 4.. so last two digits can be filled as:
12
24
32
44
52
so,here last digit can only be filled by 2 ways i.e. 2 & 4 while
second last digit can be filled by 5 ways i.e. 1,2,3,4,5
and other first 7 places can be filled in 5^7 ways as repeation is allowed.
so required result is: 5^7*5*2= 5^8*2.

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alpa sharma  (7 years ago)

For divisible by 4 we will see last 2 digits should be divisible by 4
we have 5 such no
so (5^7)* 5

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