Latest TCS Aptitude Question SOLUTION: A two digit no is 18 less than square of the sum of its digit. How many such no are there..??

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A two digit no is 18 less than square of the sum of its digit. How many such no are there..??

Asked In TCS lakshmikandhan (10 years ago)

Unsolved Read Solution (4)

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Read Solution (4) :

RAKESH  (10 years ago)

let a two digit number be (10x+y), x=tenth digit & y=unit digit

Given,
10x+y=(x+y)^2-18

(x+y)^2 should be less than 118 & greater than 28 to be two digit no.
(x+y)^2 may be 100,81,64,49,36

(x+y)^2 -18 = 10x+y
check for these
1. 100-18 = 82 => (82+18)=(8+2)^2
2. 81 -18 = 63 => (63+18)=(6+3)^2
3. 64 -18 = 46 => (46+18)=(4+6)^2 [not satisfied]
4. 49 -18 = 31 => (31+18)=(3+1)^2 [not]
5. 36 -18 = 18 => (18+18)=(1+8)^2 [not]

Hence, only 2 numbers are possible
82 & 63

Is this solution Helpfull? Yes (44) | No (3)  

SASWATA CHAKRABORTY  (10 years ago)

1234+6543=11110

Is this solution Helpfull? Yes | No (6)  

DHIRAJ KUMAR SINGH  (9 years ago)

63 & 82 are the no.s
2 ans

Is this solution Helpfull? Yes | No   

Ankit  (9 years ago)

short trick plz

Is this solution Helpfull? Yes | No   

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