Latest TCS Aptitude Question SOLUTION: 27. Find the number of zeroes in 11*22*33*44 …. 4848*4949 ?

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Number System

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40033463) TCS Numerical Ability question Keep an EYE

27. Find the number of zeroes in 11*22*33*44 …. 4848*4949 ?

Asked In TCS Tejasree (10 years ago)

Unsolved Read Solution (15)

Is this Puzzle helpful?   (23)   (16) Submit Your Solution Number System

Read Solution (15) :

Vincy S  (10 years ago)

Plz give explanation teja...

Is this solution Helpfull? Yes (7) | No (1)  

kulwant singh  (10 years ago)

11(1*2*3*.....449)=11*449!
449! contains 109 5's , so no of zeros=109

Is this solution Helpfull? Yes (7) | No (6)  

Payel Das  (8 years ago)

Question is wrong.
correct question with solution-
number of zeros in 1*2^2*3^3*4^4*....49^49

Let us count the number of 5's.

5^5 contributes 5 5's
10^10 contributes 10 5's
15^15 -> 15 5's
20^20 -> 20 5's
25^25 -> 5^50 that is 50 5's
30^30-> 30 5's
35^ 35-> 35 5's
40^40-> 40 5's
45^45 -> 45 5's

so number of 5's = 5 + 10 + 15 + 20 + 50 + 30+ 35+40+45 = 250

so there are 250 0's.

Is this solution Helpfull? Yes (7) | No   

chigs  (9 years ago)

ans is 250......actually the question is wrong ..the question is 1^1*2^2.....49^49

Is this solution Helpfull? Yes (5) | No (1)  

Arnab Dutta  (10 years ago)

think it as 4949!
we need to determinr no of 5's in it
4949/5 its quotient is 989
989/5 its quotient is 197
197/5 its quotient is 39
39/5 its quptient is 7
7/5 its quotient is 1
so, it we all all of these quotient it will gibve answer 1231 no. of 5 in 4949!
we have to reduce first 10 digits
their contains only 2 no of 5's(5 and 10)
s0, 1231-2=1229

Is this solution Helpfull? Yes (4) | No (9)  

Ajay Singh Yadav  (9 years ago)

11 22 33 ... 1111 1212 .... 2525 ....4848 4949
no of 5 in
55=1
1010=1
1515=1
2020=1
2525=2
3030=1
3535=1
4040=1
4545=1
total=10
or
u can also find no of zero in 49!=10

Is this solution Helpfull? Yes (4) | No (4)  

Santosh Kumar  (10 years ago)

Number should be a mirror image:(All we need is numbers with 5 and o in the end)
55=11*5^1
555=111*5^1,calculate in the same way
1010,1515,2020,2525,3030,3535,4040,4545......adding powers of 5,Total=11 As there are many 2's.So when 5 and 2 multiplies,zeroes will come.Answer=11

Is this solution Helpfull? Yes (2) | No   

adityesh mohanty  (10 years ago)

1229(ans)
as no.of 5s in 11*22...4949=1229

Is this solution Helpfull? Yes (1) | No   

shalini tiwari  (10 years ago)

please give solution

Is this solution Helpfull? Yes | No   

Dharmendra Ramanujan  (10 years ago)

question is wrong because the last terms 4848 and 4949 are not divisible perfectly.

Is this solution Helpfull? Yes | No (1)  

Dharmendra Ramanujan  (10 years ago)

Answer is 9

Is this solution Helpfull? Yes | No   

Radhika  (10 years ago)

Can anybody provide the answer

Is this solution Helpfull? Yes | No   

sanju  (10 years ago)

plzzz xpln it clearly

Is this solution Helpfull? Yes | No   

Priya Singh  (9 years ago)

The answer is 1230
lets !st find out how many zeros are there in 4949! by multiplying and dividing the expession by 10!.
So, no of zeros in 4949! will be 1232
the substract it by 2, ie. 1232-2=1230 (since we have 2 zeros in 10!)
So 1230 is the correct answer...

Is this solution Helpfull? Yes | No (1)  

Dinesh Kesawamoorthy  (6 years ago)

The actual question is
Find the number of zeroes in
1^1 *2^ 2 *3 ^3 *......48^48 *49^49? a) 250 b) 225 c) 545 d) 135

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.