Latest TCS Aptitude Question SOLUTION: 5^2010 what will be the sum of digits?

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5^2010
what will be the sum of digits?

Asked In TCS Ghanshyam Gulati (10 years ago)

Solved soumi sen Read Solution (7)

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Read Solution (7) :

soumi sen  (10 years ago)

5^2=25 sum of digits =2+5=7
now if we take the power of 5 and do 2*3+1=7
similarly for 5^4=625 and sum=6+2+5=13
now do 4*3+1=13
similarly, 5^2010 sum of the digits would be 2010*3+1=6031

Is this solution Helpfull? Yes (28) | No (15)  

Kore Krishna Sumanth  (9 years ago)

when power is even : 5^2=25 sum of digits =2+5=7
now if we take the power of 5 and do 2*3+1=7
when power is odd 5^9=1953125 sum of digits=1+9+5+3+1+2+5=26
now do 9*3-1=26
Similarly 5^2010 sum=2010*3+1=6031

Is this solution Helpfull? Yes (6) | No (4)  

nandita shrivastava  (9 years ago)

@zishan khan..the solution given by soumi singh is correct for powers which are even..try it for any power which is even d ans will be correct..but yes the question is wat to do wen poweris odd

Is this solution Helpfull? Yes (4) | No (1)  

KRISHNA CHANDRA UPADHYAY  (9 years ago)

5^2=25 sum of digits =2+5=7
now if we take the power of 5 and do 2*3+1=7
similarly for 5^4=625 and sum=6+2+5=13
now do 4*3+1=13
similarly, 5^2010 sum of the digits would be 2010*3+1=6031

Is this solution Helpfull? Yes (2) | No (2)  

MODI SURYA HARSHA  (10 years ago)

for 5^9=1953125
sum of digits is 26
according to your rule 9*3+1=28.

Is this solution Helpfull? Yes (1) | No (1)  

chumki dutta  (8 years ago)

the ans should be 6031 but method will be different.

5^1=5
5^2=25 sum of digits=7
5^3=125 sum of digits=8
5^4=625 sum of digits= 13
and so on..
if you look carefully then one pattern is definite
that when the power of 5 is even then the sum of digits are increased by +6
like 7,13,19 ..so on
so as 2010 is even then in 2010/2=1005 th even number
then 7+(1005-1)*6=6031
so that is the answer.

Is this solution Helpfull? Yes (1) | No   

Zishan Khan  (9 years ago)

Check your rule for 5^5
5^5 = 3125
i.e, 3+1+2+5 = 11

Is this solution Helpfull? Yes | No (1)  

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