Latest TCS Aptitude Question SOLUTION: 20 men shake hands with each other. Maximum no of handshakes without cyclic handshakes.

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20 men shake hands with each other. Maximum no of handshakes without cyclic handshakes.

Asked In TCS (10 years ago)

Solved RAKESH Read Solution (19)

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Read Solution (19) :

RAKESH  (10 years ago)

1st person will shake hand with 19 people
2nd person will shake hand with 18 people
3rd person will shake hand with 17 people
......

total no. of handshakes = 19+18+17+...+3+2+1 = 19*(19+1)/2 = 190


or, if there are n persons then no. of shakehands = nC2 = 20C2 = 190

Is this solution Helpfull? Yes (53) | No (7)  

Ann Theressa  (10 years ago)

190

no of handshakes = 19+18+17+...+2+1
= 19*20/2 ==>[sum of n numbers = n(n+1)/2]
= 190

Is this solution Helpfull? Yes (8) | No   

Rohit Agarwal  (10 years ago)

Maximum number of handshakes=nc2
if there are n peoples
so 20c2 handshakes.

Is this solution Helpfull? Yes (7) | No   

Saraswathy  (10 years ago)

No. of handshakes ll = n(n-1)/2

= 20 (19)/2

=190 handshakes

Is this solution Helpfull? Yes (6) | No (1)  

krishna murari mishra  (10 years ago)

(20*19)/2=190
e.g-let there was 5 people,we hv to find total no. of handshake,so
starting from 1st person,he shook hand wid 4 other people,and completed his turn,so total no. of h.s-4,now come to 2nd person ,he shook with other 3 people and completed his turn,so in this case total no of H.S-3,now come to the 3rd person,he does the same,so total no. of H.S-2,now the 4th have only 1 choice.
here summing all the above we get---4+3+2+1=10((5*4)/2).
we can try it wid othr e.g.

Is this solution Helpfull? Yes (3) | No   

Sandeep Singh  (9 years ago)

the ans is 20C2 =100

Is this solution Helpfull? Yes (2) | No   

anusha  (10 years ago)

190

1st person shake hand with 19 people
2nd person shake hand with 18 people
.
.
.
.
total=19+18+17+.............+1=n(n+1)/2
(19*20)/2=19*10=190

Is this solution Helpfull? Yes (1) | No   

sruthi  (10 years ago)

19+18+17+16+15+14+13+12+11+10+9+8+7+6+5+4+3+2+1=190

Is this solution Helpfull? Yes (1) | No   

shubham malhotra  (9 years ago)

its a simple quation of combunation
20C2 = !20/!18*!2 = 190

Is this solution Helpfull? Yes (1) | No   

vikas kesarwani  (9 years ago)

vikas
If there are n number of people then total number of handshakes are
n(n-1)/2
20*19/2=190

Is this solution Helpfull? Yes (1) | No   

Goldi kumari  (9 years ago)

n(n-1)/2=20(20-1)/2
20*19/2=190

Is this solution Helpfull? Yes (1) | No   

manisha kumari  (9 years ago)

20 men can shake hands only with 19 men.hence n*(n-1)/2= 20*19/2=190

Is this solution Helpfull? Yes (1) | No   

saumya shukla  (9 years ago)

19.........for not forming cycle it needs 1 less men

Is this solution Helpfull? Yes (1) | No (1)  

Kavita Tewani  (10 years ago)

If there are n number of people then total number of handshakes are
n(n-1)/2
20*19/2=190

Is this solution Helpfull? Yes | No (1)  

Supriya_kamkar  (9 years ago)

n(n-1)/2=(20*(19))/2=380

Is this solution Helpfull? Yes | No (2)  

deepak pandey  (9 years ago)

maximum no of handshakes=n(n-1)/2
20*19/2
answer is 190...

Is this solution Helpfull? Yes | No   

Puja Dutta  (9 years ago)

20c2 handshakes without cyclic is 190 handshakes

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Sourav Sakar  (9 years ago)

10 men can shake hands with only 10 people , when they are shaking hands with each other. ( without cyclic handshakes)

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shanu chauhan  (8 years ago)

1st person will shake hand with 19 people
2nd person will shake hand with 18 people
3rd person will shake hand with 17 people
......

total no. of handshakes = 19+18+17+...+3+2+1 = 19*(19+1)/2 = 190


or, if there are n persons then no. of shakehands = nC2 = 20C2 = 190

Is this solution Helpfull? Yes | No   

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