Latest AIEEE Aptitude Question SOLUTION: given three points P,Q,R WITH P(5,3) and R lies on x-axis.if equation of RQ is x-2y=2 and PQ is parallel to x-axis then the centroid of triangle PQR lies on the line

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(#M40034877) AIEEE Numerical Ability question Keep an EYE

given three points P,Q,R WITH P(5,3) and R lies on x-axis.if equation of RQ is x-2y=2 and PQ is parallel to x-axis then the centroid of triangle PQR lies on the line

Asked In AIEEE Jathin Sai (10 years ago)

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Ann Theressa  (10 years ago)

(5,2)

P (5,3)

equation of RQ is
x - 2y = 2

Given R lies on x-axis. So at point R y co-ordinate is 0
x - 2*0 = 2
x = 2

R (2,0)

PQ is parallel to x axis
===> y co-ordinate of Q and P are same. ie 3

From equation of RQ
x - 2*3 = 2
x = 8

Q (8,3)

Centroid = ((x1+x2+x3)/3 , (y1+y2+y3)/3 )
=((5+2+8)/3 , (3+0+3)/3)
=(5,2)

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animesh  (9 years ago)

the centroid can lie on any line bcuz infinite lines (ex. y=2 or x=5 and so on)can cross through a point in this case the centroid is at(5,2).

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Chirag Ranjan Lahiri  (9 years ago)

the centroid is at(5,2)

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