Latest zoho Aptitude Question SOLUTION: How many small cuboids of dimension 2m X 3m x 4 m can be accommodated in a cube of side 22 m?

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(#M40037621) ZOHO Numerical Ability question cuboid Keep an EYE

How many small cuboids of dimension 2m X 3m x 4 m can be accommodated in a cube of side 22 m?

Asked In zoho amarnath kamaraj (9 years ago)

Unsolved Read Solution (17)

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Vibhanshu Shukla  (9 years ago)

2*3*4=24
22^3=10648
then 10648/24=443

Is this solution Helpfull? Yes (28) | No (31)  

Vinoth Anandan  (9 years ago)

I guss 385

take one side first
22 for large and 4 for small (4 is 1st larger side)
22/4=5.5 => 5
take next side first
22 for large and 3 for small (3 is 2nd larger side)
22/3=7.333 => 7
take next side first
22 for large and 2 for small
22/2=11
So 5*7*11= 385

Is this solution Helpfull? Yes (23) | No (8)  

kalaiamuthan manisekar  (8 years ago)

no of cuboids= surface area of cube / surface area of cuboid
= ( 6a^2 ) / ( 2(lb+bh+lh) )
= ( 6*22*22 ) / ( 2(2*3+3*4+2*4))
= 726 / 13
= 55 cuboids

Is this solution Helpfull? Yes (6) | No (9)  

KUMARAN  (8 years ago)

it might be 385
coz the question is how many small cuboids with 2*3*4 with the cube's side of 22m
then
for taking sides differently
we may get 11,7,5
totally 11*7*5 =385

Is this solution Helpfull? Yes (5) | No (8)  

ashwin  (8 years ago)

385 small cuboids can be accommodated.The cube cannot hold half a cuboid so dimensions will have remainders 0*1*2 respectively.Now volume of accommodated cube is 22*21*20 and no. of cuboids=22*21*20/(2*3*4)=385

Is this solution Helpfull? Yes (3) | No (2)  

PRIYADHARSHINI  (7 years ago)

I think 420

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nithin shyam  (7 years ago)

Arrange the cuboids along the 2m sides on an edge of the 22 m cube.
Total cuboida in a row = 22/2=11
No. of cuboids along the 3m edge = 22/3 ~= 7
No. of cuboids along the height of the cube = 22/4 ~= 5
So, total no. of cuboids = 11*7*5 = 385

Is this solution Helpfull? Yes (2) | No   

Dayashri  (8 years ago)

The 2 digit Number is 81.
Here lets give a bottom up approach to proceed easily.
the 2 digit perfect square numbers are 16,25,36,49,64,and 81.
Lets proceed from the larger number 81-> sum of the digits=9
81/9=9(SQRT of 81)...
Hence the 2 digit is 81..

Is this solution Helpfull? Yes (1) | No (5)  

VAMSHI PRIYA VORUGANTI  (7 years ago)

can any one give a proper solution to it?

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priya  (7 years ago)

ans is 420

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Kausalya selvakumar  (7 years ago)

443 cuboids. cube volume=22^3 ; cuboid volume = 2*3*4=24;
no of cubboids accomodated in this cube = 10648/24 = 443.67= 443 cuboids.

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CHARUMATHI MC  (6 years ago)

1.Arrange the cuboids along the 2m sides on an edge of the 22 m cube.
Total cuboida in a row = 22/2 = 11
2.No. of cuboids along the 3m edge = 22/3 ~= 7
3.No. of cuboids along the height of the cube = 22/4 ~= 5
So, total no. of cuboids = 11*7*5 = 385
NOTE:You can't go by volume as it is a cuboid not a cube.

Is this solution Helpfull? Yes (1) | No   

Kausalya selvakumar  (6 years ago)

No.of cuboids= volume of cube/ volume of cuboid
= (22*22*22)/(2*3*4)
=10648/24
=443 cuboids.

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niranjanan  (7 years ago)

I guess the question is given wrong.,....:)

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elango  (7 years ago)

for free apps classes plz contact DR.ELANGO 9551026952, elangocruzer@hotmail.com

Is this solution Helpfull? Yes | No (8)  

Renuga  (7 years ago)

Wat s d crct ans??

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saravana  (7 years ago)

I guess its 443.6666667
multiply the given small cuboids dimensions 2x3x4=24
then multiply the cube of side 22 i.e 22x22x22=10648
divide 10648/24 =443.6666667 so take it as 440 cubes.

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