Latest Huawei Aptitude Question SOLUTION: find the day of the week on 25th december 1995

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find the day of the week on 25th december 1995

Asked In Huawei Gayathri (9 years ago)

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Sasikumar  (9 years ago)

1600 years - 0 odd days
300 years - 1 odd day
94 years - 5 odd days
1995'th year - 2 odd days

1+5+2 / 7 = 1 odd days

Monday.

Is this solution Helpfull? Yes (16) | No (6)  

Sneha Priyadarshini  (9 years ago)

Last two digit of the year= 95
95 divided by 4 =23 as quotient.
Code of the dec month =6 [ Code of months - ( JAN : 1 , FEB : 4 , MAR : 4 , APR : 0 , MAY : 2 , JUNE : 5 , JULY :0 , AUG : 3 , SEP : 6 , OCT : 1 , NOV : 4 , DEC : 6 )]
Given Date =25

ADD : 95 + 23 + 6 + 25 =149
149 / 7 = 2 as a remainder i.e. Tuesday.
[ MON : 1 , TUES : 2, WED : 3 ,THURS : 4 , FRI : 5 , SAT : 6 , SUN : 0]
So, ans is TUESDAY.

Is this solution Helpfull? Yes (9) | No (12)  

vinay B V  (9 years ago)

tuesday.
for 1900 yrs-15 odd days.
for 94yrs-6 odd days.
upto dec 25-51 odd days.
15+6+51=72
72/7=rem 2
if rem=0,sunday
1=monday,2=tuesday n so on.
so ans is tuesday.

Is this solution Helpfull? Yes (3) | No (6)  

DEEPA RAM CHOUDHARY  (9 years ago)

1600 year-0 odd days
300 year-(5*3)/7=1 odd days
94 year (23*2+71)/7=5 odd days
1995th year -(31+28+31+30+31+30+31+31+30+31+30+25)/7=2 odd days

(1+5+2)/7=1 odd days
monday

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Sreenivasa Raju Chamarthi  (8 years ago)

25-DEC-2015

day codes --> Sun - 0, Mon-1, Tue-2, Wed-3, Thu-4. Fri-5, Sat-6.

month codes --> Jan-0, Feb-3, Mar-3, Apr-6, May-1, Jun-4, Jul-6 , Aug-2, Sep-5, Oct-0, Nov-3, Dec-5.

Century Codes --> 1600-1699 -- 6
1700-1799 -- 4
1800-1899 -- 2
1900-1999 -- 0
2000-2099 -- 6

step-1:
take DATE and LAST TWO DIGITS OF YEAR then add those two numbers.

25+95=120

step2:

Divide last two digits of the year with 4 and then take quotient into consideration.

95/4=23(quotient).

step3;

step1 + step2 + cetury code + month code

120+23+0+5=148

step4:

divide the resultant value with 7 and then take the remainder into consideration

148/7=1(remainder)


1 means monday

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PRIYA  (9 years ago)

1900-1999=0 odd days.
december=5
25(date)+95(last 2 value of year)=120
divide last 2 digits of year by 4 and take quotient value alone.
95/4=23
# 23+120=143
143+5(month code of dec)=148
divide the final answer by 7.
148/7=21+1
ANs:monday.

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Akash Dixit   (9 years ago)

@Sneha, Acc. to ur concept, the ans of my another ques. " Ques. June 30, 2004 is wednesday. What is June 30, 1974? " should be Monday (as 74+18+30+5 = 127, and 127 / 7 = 1) ...But the Ans is not Monday...Ans is Sunday............Now fix it....!!

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sunil  (9 years ago)

what is month code in last(priya) solution?

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aamir rafiq  (8 years ago)

for 1600 years - 0 odd day

for 300 years - 1 odd day

94 years - (94/4) gives 23 leap year & 71 normal year
hence (23*2 + 71*1) /7 = 5 odd days....{leap year has 2 odd year hence 23*2 & normal year has 1 odd day hence 71*1 }

1995th year - (365-6)= 359/7= 2 odd days {as we are finding for 25th December and 1995th year has 365 days hence to find 25th of December we would minuus 6 from total days that id 365}.

add all the odd days and divide from 7 the accordingly:-

1+5+2 / 7 = 1 odd day

hence for 1=Monday is right answer

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rajesh  (8 years ago)

consider last two digits of year i.e. 95
95/4=23
consider date 26
the code of months is 0(jan),3(feb),3,6,1,4,6,2,5,0,,3,5(dec)
so the code of december is 5
add all values i.e. 95+23+26+5=148
then 148 % 7=1(remainder)
codes of days is 0(sun),1(mon),2,3,4,5,6(sat)
so the day is MONDAY.

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