Latest IBM Aptitude Question SOLUTION: In 1930 the father's age is 8 times of son's age. in 1938 father's age is 10 times of son's age in 1930. in 1940 what is their age's

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In 1930 the father's age is 8 times of son's age. in 1938 father's age is 10 times of son's age in 1930. in 1940 what is their age's

Asked In IBM juhe rawat (9 years ago)

Unsolved Read Solution (6)

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Sharmila Devi Ghantasala  (9 years ago)

In 1930 f=8s; In 1938 I.e 8 years after f+8=10*s;
8s+8=10s=>s=4
Therefore f=8*4=32 in 1930;
In 1940 I.e after 10 years f=42,s=14

Is this solution Helpfull? Yes (26) | No (1)  

tirupathi reddy  (9 years ago)

Ans 42, 14

In 1930
F=8S------1

In 1938
(F+8)=10S----2

By solving 1 and 2 we get
Fathers age 32
Son age 4

After ten years their ages are 42 and 14.

Is this solution Helpfull? Yes (3) | No (1)  

sudha  (9 years ago)

In 1930 age of son be = y
In 1930 father age is 8 times of son's age.... so if father age be x
i.e x=8y-----> 1

in 1938 father age will be
(x+8)=10 *(y) ----->2
solve 1 and 2

x+8= 10y---->3
8y+8=10y
y=4--->son age in 1938
put y value in equation 3
you will get fathers age

x+8=10*4
x=32 ----> father age in 1938

so in 1940 father's age ll be...x+2
x=34
similarly,
son age in 1940 is y=6

Is this solution Helpfull? Yes (2) | No (5)  

Ajay Dubey  (9 years ago)

in 1930
son=x
f=8x
in 1938
8x+8=10x
x=4
so age in 1940 are
son=4+10=14
father=8*4+10=42




















8

Is this solution Helpfull? Yes (2) | No (1)  

ABHISHEK SAW  (9 years ago)

let in 1930 son's age be x so his father's age should be 8x
in 1938 son's age =x+8 & father's age =10x
so,10x-8x=8,x=4
so,in 1940 son's age=x+10=4+10=14 & father's age=8x+10=42

Is this solution Helpfull? Yes (1) | No   

muni p  (9 years ago)

14,42 because of their age in 1930 ....4,32

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