Latest Elitmus Aptitude Question SOLUTION: a2+ab+b2=259 b2+bc+c2=1299 c2+ac+a2=499 then a+b+c=?????

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(#M40038060) ELITMUS Numerical Ability question Alzebra Keep an EYE

a2+ab+b2=259
b2+bc+c2=1299
c2+ac+a2=499
then a+b+c=?????

Asked In Elitmus Hirak Das (9 years ago)

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SURENDAR TEJAVATH  (9 years ago)

26
put a2+ab+b2=(a3-b3)/(a-b) and add three terms

Is this solution Helpfull? Yes (4) | No (7)  

amrita kumari  (9 years ago)

option plz...

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pavan  (9 years ago)

ans:38.5 make all terms as perfect squares

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Kataria Deepak  (9 years ago)

Wrong Que..
a^2*b^2+a^2+b^2+1= (a^2+1)(b^2+1)
by using above one we can write
a^2*b^2+a^2+b^2+1=260..(1)
b^2*c^2+b^2+c^2+1=1300..(2)
c^2*a^2+c^2+a^2+1=500..(3)
by doing (1)/(2) we will get a^2+1/c^2+1 = 1/5..(4)
by doing (4)*(3) we will get (a^2+1)^2=10,
by solving a=3, b=5,c=7
so a+b+c=15

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