Latest Book Aptitude Question SOLUTION: (32^32^32)/7 what will be the remainder

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(#M40038446) BOOK Numerical Ability question Keep an EYE

(32^32^32)/7
what will be the remainder

Asked In Book tauseef arbab (9 years ago)

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Shivankur Pal  (9 years ago)

remainder=4

(32^32^32)/7
using remainder theorem---

(((4)^32)^32)/7.............32/7 gives rem 4
((((4)^2)^16)^32)/7
(((16)^16)^32)/7.............16/7 gives rem 2
(((2)^16)^32)/7
((2(2)^15)^32)/7
((2(8)^5)^32)/7
((2)^32 x 1)/7............ 8/7 gives rem 1
(4(8)^10)/7
4 x 1 ................ 8/7 gives rem 1
=4 !!!!!!

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madhurima  (9 years ago)

ANS WILL BE 1.
DIVING 32 BY 7,WE GET 4 AS REMAINDER.
NOW THE SITUATION IS:(4*4*4)/7=(16*4)/7
AGAIN DIVING 16 BY 7,2 IS THE REMAINDER
(2*4)/7=8/7 WHICH GIVES 1 AS REMAINDER.

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Pranoy Bej  (9 years ago)

(32^32^32)/7 using remainder theorem
32/7 = 4 remainder
now (4^32^32)/7= (4^2^16^32)/7 =(2^16^32)/7=(2^4^32)/7=(2^32)= gives remainder 2^2 = 4

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