Latest TCS Aptitude Question SOLUTION: find the number of 6 digit numbers that can be formed using digits 1,2,3,4,5,6 once such that the 6digit number is divisible by its unit digit.

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Permutation and Combination

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40038587) TCS Numerical Ability question Keep an EYE

find the number of 6 digit numbers that can be formed using digits 1,2,3,4,5,6 once such that the 6digit number is divisible by its unit digit.

Asked In TCS SHUBHAM SONI (9 years ago)

Solved Satya Karteek Read Solution (11)

Is this Puzzle helpful?   (14)   (6) Submit Your Solution Permutation and Combination

Read Solution (11) :

Satya Karteek  (9 years ago)

Answer is 648.
There are 6 numbers which can be placed in units digits.
case 1: When the unit digit is 1,2,3,5,6 whatever the other numbers are the 6 digit number will be surely divisible by the unit digit.
Hence the 5 numbers in the units place can be placed in 5 ways and the remaining 5 numbers can be arranged in 5! ways.
5*5!=600 ways
Case 2: If the unit digit is 4, then the tens digit should be 2 or 6, hence 24 or 64 can be arranged in the last two places in 2 ways and the remaining 4 numbers can be arranged in 4 places in 4!ways.
2*4!=48 ways


Total no.of.ways= 600+48 = 648 ways.

Is this solution Helpfull? Yes (72) | No (8)  

RAKESH  (9 years ago)

when unit digit 1,2,3,5,6 then no. formed will be divisible by the digit at the unit place.
=> 5*5p5 numbers

when unit place is 4, tenth place should be 2 or 6
=> 2*4p4 numbers

total = 5*5p5 + 2*4p4 = 5*5! + 2*4! = 648

Is this solution Helpfull? Yes (23) | No (5)  

karthikeyank  (9 years ago)

Ans:528
Digits 1,2,3,4,5,6
When unit digit is 2,3,4,5,6
When unit digit is 2 it is divisible 2
5!=120
When unit digit is 3 it is divisible 3
5!=120
Similarly for unit digit 5 and 6
the number of required numbers is 120 each
When unit digit is 4 it is divisible by both 2 and 6
2*4!=48
Total=4*120+48=480+48=528 is Ans

Is this solution Helpfull? Yes (9) | No (18)  

RISHABH  (9 years ago)

5*5!+2*4!
=648

Is this solution Helpfull? Yes (3) | No (5)  

karthikeyank  (9 years ago)

Ans:528
Digits 1,2,3,4,5,6
When unit digit is 2,3,4,5,6
When unit digit is 2 it is divisible 2
5!=120
When unit digit is 3 it is divisible 3
5!=120
When unit digit is 3 it is divisible 3
5!=120
Similarly for unit digit 5 and 6
the number of required numbers is 120 each
When unit digit is 4 it is divisible by both 2 and 6
2*4!=48
Total=4*120+48=480+48=528 is Ans

Is this solution Helpfull? Yes (2) | No (19)  

bandi vinay  (9 years ago)

720
6 digits numbers can be formed i.e 6!=6*5*4*3*2*1=720

Is this solution Helpfull? Yes (1) | No (2)  

Vikas Sharma  (9 years ago)

528 is right answer.....its cat quant.(permutaion &combination) level 1(q-59)

Is this solution Helpfull? Yes (1) | No   

manojkvn  (9 years ago)

unit digit no of possibilites
1 5!
2 5!
3 5!
4 4!*7
5 5!
6 5!
total no possibilities 5*5!+4!*7=768

Is this solution Helpfull? Yes | No (6)  

pardeep  (9 years ago)

according to me ans is 648.

Is this solution Helpfull? Yes | No (2)  

Sameer Saurabh  (9 years ago)

5!*5=600
4!+4!+600= 648 ans

Is this solution Helpfull? Yes | No (2)  

vamsi  (9 years ago)

when the unit digit is 1,2,3,5,6 the remaining digits will be divided by them so 120+120+120+120+120
when unit digit is 4 then its corresponding tens digit must be 2 or 4 so it can be arranged in 2*4! ways so total is 600+48=648 ways

Is this solution Helpfull? Yes | No (1)  

Please Login to Read Solution.