Latest TCS Aptitude Question SOLUTION: Find the probability that a leap year chosen at random has 53 sundays?

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Find the probability that a leap year chosen at random has 53 sundays?

Asked In TCS Tarun Sinha (9 years ago)

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karthikeyank  (9 years ago)

Ans:2/7
A leap year has 366 days
52 weeks and 2 more days
The last 2 days can be Following from
(sunday,monday)
(monday,tuesday)....(saturday,sunday)
There are 7 combination
2 scenarious(days) out of 7 have 53rd sundays

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jitendra varshney  (9 years ago)

Sol.: A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days.

The remaining 2 days may be any of the following :

(i) Sunday and Monday

(ii) Monday and Tuesday

(iii) Tuesday and Wednesday

(iv) Wednesday and Thursday

(v) Thursday and Friday

(vi) Friday and Saturday

(vii) Saturday and Sunday

For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday.

n(S) = 7

n(E) = 2

P(E) = n(E) / n(S) = 2 / 7

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RITESH KUMAR  (9 years ago)

2/7
because leap year has 2 odd days so probability of a sunday is 2/7

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Madine Raju  (9 years ago)

366=7*52+2
the possibility is Sunday&Monday, Mon&Tue, Tue&Wed, Wed&Thu, Thu&Fri, Fri&Sat, Sat&Sun SO THE PROBABILITY IS 2/7

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karthik Kumar reddy  (9 years ago)

ans is 2/7

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G.Mounika  (9 years ago)

in leap year there are 366days.
52 weeks means 364 days.
in one year there are 52 weeks so 52weeks+2days
2odd days sat+sun,sun+mon
so 2/7

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prabhjot  (9 years ago)

ans is 2/7.
366=7*52+2.

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riya ghosh  (9 years ago)

there are 52 weeks + 2 days in a leap year(366=52*7 + 2).ie 52 sundays.
these extra 2 days can be sun+mon , mon+tue,......sat+sun.so to have 53 sundays one of these consecutive must be a sunday. there are 2 such possibilities out of 7 possibilities. hence reqd probability = 2/7

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prabhjot  (9 years ago)

2/7 is the ans
beacuse 52*7=364 the 2 days are left
so there are 2 chances of occuring of sunday.

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pooja chavan  (9 years ago)

2 day
leap yr has 366 days
so52*7=364
2 days can be in pair of sat-sun and sun-mon pair

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