Latest TCS Aptitude Question SOLUTION: 325^325/125^n????

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(#M40038815) TCS question Keep an EYE

325^325/125^n????

Asked In TCS aditi gakhar (9 years ago)

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karthikeyank  (9 years ago)

Ans:216
325^325/125^n
325^325 = 325*325*325.................325 times
and 125 = 5*5*5
also 325 = 5*5*13 (2 fives)
in 325 times 325 we have 5^(2*325) which we can write in (5^3)^216
so the answer is 216

Is this solution Helpfull? Yes (5) | No (7)  

Avinash Gupta  (9 years ago)

On solving we get n= 216

Is this solution Helpfull? Yes (3) | No (6)  

surbhi dubey  (9 years ago)

@KARTHIKEYANK .....can u please explain it properly

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SUMANTA SAMANTA  (9 years ago)

325^325/125^n
The factor of 125= 5*5*5 = 5^3
The factor of 325= 5*5*13 = (5^2)*(13^1)
so Now 325^325 means = (5^2)^325 * (13^1)^325 = 5^650 * 13^325 ----1
As 125^n = (5^3)^n =5^3n ----2
so (1)/(2)
= (5^650)*(13^325)/(5^3n)
3*n=650
n will be multiple of 3 then only it will divisible properly other wise not . 3*216=648 .but here if i do 3*217=651 but it is larger than 650
Ans : 216

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harish  (9 years ago)

what is n???

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abhe chandu  (9 years ago)

explain it properly

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Raghav gupta  (9 years ago)

answer is 216 as 325=5*5*13 and 125=5 *5* 5 so when we write 325^ 325 it is actually equal to 5^650*13^325 if this number is to be completely divisible by 125 that means 5^3n the power of 5 in 325 should be a multiple of 5 so that it is completely divisible by 5^3 we take 5^648 * 5^2 * 13^325/5^3n n comes out to be 216.

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