Latest TCS Aptitude Question SOLUTION: What is the distance between two parallel chords of length 24 cm and 32 cm in a cirle of radius 20 cm ? (a) 4 or 28 (b) 1 or 7 (c) 2 or 14 (d) 3 or 21

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What is the distance between two parallel chords of length 24 cm and 32 cm in a cirle of radius 20 cm ?

(a) 4 or 28
(b) 1 or 7
(c) 2 or 14
(d) 3 or 21

Asked In TCS sourav chandan (9 years ago)

Unsolved Read Solution (7)

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Read Solution (7) :

MUNISH YADAV  (9 years ago)

There are two possibilities: Either the chords are on the opposite side of the diameter OR on the same side.
Let the distances of the chords 24cm and 32cm from the center be x&y.
x^2+12^2=20^2 i.e x=16
y^2+16^2=20^2 i.e y=12
Thus, distance between the chords can be 16+12=28cm or 16-12=4cm....option(a)

Is this solution Helpfull? Yes (16) | No (1)  

ashvini kumar  (9 years ago)

suppose that given chords are parallel to diameter of circle
chord ab=24
chord cd=32
let m is perpendicular to ab from centre o such that am=mb
let n is perpendicular to cd from centre o such that cn=nd
in tringle omb and ond ob=od=radius of circle=20
in tringle omb mb=ab/2=12
so om=sqrt(ob,mb)=16
in tringle ond nd=cd/2=24
so on=sqrt(od,nd)=12
so distance b/w both chord:
if they are in one side of diameter=om-on=4
if they are in opposite side of diameter=om+on=28
so correct option is (a)

Is this solution Helpfull? Yes (3) | No   

Arif Ali  (9 years ago)

Radius of Circle 20
First Chord length=24
Distance1=Sqrt(20*20-12*12)
Second Chord length=32
Distance2=Sqrt(20*20-16*16)
Distance=Distance1+Distance2
or Distance=Distance1-Distance2
Ans a

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Utsav Chakraborty  (9 years ago)

R1=32 and R2=24
So R1/2+R2/2 or R1/2-R2/2 i.e 16-12=4 or 16+12=28
So ans is 4or28

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subhadra gupta  (9 years ago)

simply by using Pythagorean theorem we can calculate this taking half of both cords as base and perpendicular on center as height.
then subtracting both answers we get needed distance.

Is this solution Helpfull? Yes (1) | No   

BATHALA MUNI MOHAN  (9 years ago)

please draw the circle and chords

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ravi palla  (9 years ago)

form two triangles, OAB and OCD
OA,OB,OC,OD=circle radius
DISTANCE= sqrt(400-144)+sqrt(400-256)=27
sqrt(400-144)-sqrt(400-256)=4

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