Latest Accenture Aptitude Question SOLUTION: find a probability that a leap year contains 53 sundays

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(#M40038962) ACCENTURE Numerical Ability question numerical Keep an EYE

find a probability that a leap year contains 53 sundays

Asked In Accenture S B HARISH (9 years ago)

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Read Solution (8) :

Anita Yadav  (9 years ago)

2/7
in leap yr there is 366 days
366/7=52 and 2 remainder
so ans is. 2/7

Is this solution Helpfull? Yes (17) | No (1)  

saravanan  (9 years ago)

a leap year has 366 days and it has 53 days so

it can be done as follows:

366c53

Is this solution Helpfull? Yes (2) | No (1)  

deepak mishra  (9 years ago)

2/7
As 366/7 is 52 and remaineder is 2
So 2/7.

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keerthana  (9 years ago)

366/7=2 odd days...
2/7 is answer

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Amit Kumar  (9 years ago)

no. of days in a weak=7
in 7 days there are two situation
1 sat and sun
2 sun and mon
so, probabilty=2/7

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Neha Shahi  (9 years ago)

ANS=2/7
becoz a leap year= 52 weeks and 2 days, now in every week we have 21 sunday
so 52 sundays in 52 weeks and the left two days can be any one of the below
(Monday,tuesday), ( Tuesday,wednesday) (Wednesday, thursday) (Thursday , friday) (Friday,
saturday) (Saturday, sunday) (sunday,monday)
hence out of 7 potions 2 include sunday: ans=2/7

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ARTI KUMARI  (9 years ago)

Leap year have 366 days
and probability of having 53 sundays=28/97

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Shantanu Smart  (9 years ago)

2/7 as 366 days and remainder comes 2 when it is divided by 7.

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