Latest TCS Aptitude Question SOLUTION: 1,5,6,25,30,31.... find the 99th term of the series

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(#M40039201) TCS Numerical Ability question series Keep an EYE

1,5,6,25,30,31....
find the 99th term of the series

Asked In TCS Aayushi jain (9 years ago)

Unsolved Read Solution (6)

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Read Solution (6) :

arpit shukla  (9 years ago)

i think there will be 26 in between 25 and 30.
2nd term =1st term *5(1*5=5)
3rd term =2nd term +1(5+1=6)
ie.
12th term =5*6th term
24th term =5*12th term
48th term =5*24th term
49th term =48th term+1
98th term =5*48th term
99th term =98th term+1
hence ans is 18756

Is this solution Helpfull? Yes (7) | No (8)  

anudeep  (9 years ago)

2nd term =1st term *5 ,i.e 1*5=5
3rd term =2nd term +1 i.e 5+1=6
4th term = 2nd term*5,i.e 5*5=25
5th term = 4th term+1,i.e 25+1=26
6th term = 3rd term*5,i.e6*5= 30
.
.
.
12th term =6th term*5
24th term =12th term*5
48th term =24th term*5
49th term =48th term+1
98th term =49th term*5
99th term =98th term+1,i.e 18755+1=18756
hence answer is 18756.

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Aniruddha  (9 years ago)

It goes like let x be position of number in series.
so
for 1, x=1
for 5, x=2
for 6, x=3

and element at x decided the (2*x)th and (2*x+1)th element.

as 1 deides, 1*5, 1*5+1
then 5 decides, 5*5,5*5+1

Is this solution Helpfull? Yes | No (5)  

ddgf  (9 years ago)

plz xplain it..

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Ankit  (9 years ago)

1,5,6 ,25, 26,30,31, 125,126,130,131,150,151,155,156,………………

1st term gives 2nd and 3rd term. .
1st term* 5= 5(2nd term)
2nd term +1=6(3rd term)
multiply current position by 2 gives the position of term which is multiplied by no 5
2nd term gives 4th and 5th term. .
likewise check for others
15th term gives 30th and 31st term. .
ans:15th term*2=30th term
so that 156*5=780(30th term)
31st term is 780+1=781

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Deepak kumar singh  (8 years ago)

ans = -2,0,1,2

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