Latest TCS Aptitude Question SOLUTION: Three distinct single digit no A,B,C are in G.P. If abs(x) for real x is the absolute value of x(x if x is positive or zero, and x if x is negative),then the no. of different possi

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Three distinct single digit no A,B,C are in G.P. If abs(x) for real x is the absolute value of x(x if x is positive or zero, and x if x is negative),then the no. of different possible values of abs(A+B-C) is
options
6
4
3
5

Asked In TCS Neerajita pal (9 years ago)

Solved Narasapu Hari prasad Read Solution (5)

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Read Solution (5) :

Narasapu Hari prasad  (9 years ago)

ans 5
if a=1,r=2 then a=1,b=2,c=4 then abs(a+b-c)=1
if a=1,r=3 then a=1,a=3,a=9 then abs(1+3-9)=5
if a=2,r=2, then a=2,b=4,c=8 then abs(2+4-8)=2
if a=1,r=-2 then a=1,b=-2,c=4 the abs(1-2-4)=5
if a=1,r=-3 then a=1,b=-3,c=9 then abs(1-3-9)=11
if a=2,r=-2 then a=2,b=-4,c=-8 then abs(2-4-8)=10

so total 5 abs() values

Is this solution Helpfull? Yes (21) | No (5)  

Aayushi Gupta  (9 years ago)

is this question recently asked in tcs???

Is this solution Helpfull? Yes (5) | No (9)  

pragathi anantha  (9 years ago)

possible a,b,c are
1,-3,9
1,-2,4
1,2,4
1,3,9
(1-3-9),(1-2-4),(1+2-4),(1+3-9)abs values are 11,5,1,5 respectively.
so ans might be 3

Is this solution Helpfull? Yes | No (1)  

nazish khanam  (9 years ago)

possible ABC are
1 3 9
1 2 4
2 4 8
1 -3 9
1 -2 4

2 -4 8
so possible values of A+B-C are
1 2 5 10 11
so possible ans is 5

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Akshaya  (6 years ago)

d)4-ans.
A,B,C may be
(1,2,4) & (4,2,1)
(1,3,9) & (9,3,1)
(2,4,8) & (8,4,2)
(4,6,9) & (9,6,4)

find abs(A+B+C) for these 8 GPs
7,13,15,19

So,we get 4 different values

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