Latest Elitmus Aptitude Question SOLUTION: In the pack of 52 cards if person select 3 card randomly find probablity that selection of king, queen, jack??

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(#M40039526) ELITMUS Numerical Ability question Probablity Keep an EYE

In the pack of 52 cards if person select 3 card randomly find probablity that selection of king, queen, jack??

Asked In Elitmus Prashant Baghel (9 years ago)

Unsolved Read Solution (12)

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Narasapu Hari prasad  (9 years ago)

ans is 64/22100.
there are 4 kings,4 queens and 4 jacks in the pack of 52 cards.
so there are 4*4*4=64 ways of selecting king,queen,jack
and there are 52c3=22100 ways of selecting 3 cards from 52 cards
so required probability=4*4*4/52c3=64/22100

Is this solution Helpfull? Yes (26) | No (6)  

Prashant Baghel  (9 years ago)

I put my answer (4/52)*(4/51)*(4/50) :-/ is that right answer pls tell me

Is this solution Helpfull? Yes (16) | No (11)  

Aaditya Verma  (9 years ago)

6*4/52*3/51*2/50=6/5525

Is this solution Helpfull? Yes (11) | No (4)  

aparna  (9 years ago)

(4C1X4C1X4C1)/ 52C3

Is this solution Helpfull? Yes (11) | No   

gaurav kumar  (9 years ago)

1 king can be selected from 4 king in 4c1 ,same way from 4 queen 1 can be selected i 4c1 ways and jack can be selected in 4c1 ways ,total ways of selection of 3 cards fom 52 cards is 52c3,so probability=4c1*4c1*4c1/52c3=16/5225 is the answer

Is this solution Helpfull? Yes (6) | No (1)  

shivani  (9 years ago)

Using formula of nCr
12C3/52C3 =(12*11*10*9!/(9!*3*2)) * (49! * 3 *2/(52 * 51 * 50 *49!))
=22/2295
12C3 because total no. of favourable cards are 12 and we have to pick only 3
52C3 because total no. of cards are 52 and again only 3 are to be picked.

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Sumit  (9 years ago)

4C1 * 4C1 *4C1 /52C3

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RAGAVENDAR SWAMINATHAN  (9 years ago)

ans :16/5525

p(e)=n(q)*n(k)*n(j)=4/52*4/51*4/50*6=16/5525

6 no of ways the kqj can be draw from deck of cards

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Upasana Rai  (9 years ago)

probability of getting a king on your first draw is 4/52.
probability of getting a queen after a king on your second draw 4/51
jack after a king and a queen 4/50
So the probability of getting a king, then a jack, and then a queen is (4*4*4)/(50*51*52).=16/5525

There are six orders that give you a king, a queen and a jack.

KQJ, KJQ, QKJ, QJK, JKQ, JQK

So, we take the original probability and multiply it by 6.

6*(4*4*4)/(50*51*52) = 16/5525

Is this solution Helpfull? Yes (3) | No (3)  

Rahul Nautiyal  (9 years ago)

i just check the answer its 6/5525... bt i put my answer (4/52)*(4/51)*(4/50)
any one knw how it is 6/5525. ?? plz explain.. plz dnt put solution like 6*(4/52)*(3/51)*(2/50)= 6/5525. i need explanation. Thanx in advance

Is this solution Helpfull? Yes (2) | No (1)  

Ganesh garg  (9 years ago)

(*4c1*4c1*4c1)/(52c3)

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ramanjulu  (9 years ago)

we have 4 of king, queen. and jack so, (4C1 * 4C1 * 4C1)/(52C3)=16/5525

Is this solution Helpfull? Yes (2) | No (1)  

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