Latest Accenture Aptitude Question SOLUTION: how many matches would have to be played to decide a winner in a knockout tournament consisting of eight teams????

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how many matches would have to be played to decide a winner in a knockout tournament consisting of eight teams????

Asked In Accenture Astha Varshney (9 years ago)

Unsolved Read Solution (9)

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siddharth anand  (9 years ago)

suppose 8 teams are.. A,B,C,D,P,Q,R,S.
We divide 8 teams into two pools
POOL1 POOL2
A P
B Q
C R
D S
POOL1 MATCHES:
A Vs B==> A WINS
C Vs D==> C WINS
A Vs C==> A WINS
----------------
3 MATCHES IN POOL1 AND WINNER IN POOL1 IS TEAM A.
POOL2 MATCHES:
P Vs Q==> P WINS
R Vs S==> R WINS
P Vs R==> P WINS
----------------
3 MATCHES IN POOL 2 AND WINNER IN POOL 2 IS TEAM P.
NOW THE FINAL WILL BE BETWEEN A AND P==> A WINS
SO TOTAL MATCHES= NO. OF MATCHES IN POOL1+NO. OF MATCHES IN POOL2+FINAL BETWEEN A AND P...i.e(3+3+1)=7 matches in total.

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a  (9 years ago)

well 1 match for 2 team ,first 8 team-4 match
4 team-2 match
2 team-1 match
total-4+2+1=7 match

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shuriya  (9 years ago)

there are 8 teams, A,B,C,D,E,F,G,H. assume A is the winner. A will play with all other team (B,C,D,E,F,G,H) remaining is 7 teams. so 7 times the winner have to play

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MajidZz  (9 years ago)

7 matches. Consider a b c d e f g h teams. a and b needs 1 match similarly other 3 pairs need 3 matches. Now we have only 4 teams and for them 2 matches for 2 winners and finally one match. 4+2+1=7

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sandeep kumar pandey  (9 years ago)

7...because its knockout so eight teams will play 4 matches after that 4 teams will qualify. now that 4 teams will play 2 matches and then 2 teams will play the final match. so total matches are 4+2+1=7

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Mohan Phanindra Reddy G  (9 years ago)

Knockout means,if we lost the match once...then we are out of tournament..
so..
Let the teams be A B C D E F G H
Let the winner be "A"
A vs B--> A wins
C vs D--> Let C wins
E vs F --> Let E wins
G vs H-->Let G wins.
so now B D F H are out of tournament.A C E G are still in the tournament and up to now 4 matches are held.
now
A vs C --> A wins
E vs F --->Let E wins... so here C and F are out.....In this round 2 matches are held.
final match is A vs E----> A Wins......E is out of tournament.....in this round 1 Match was held.
So totally 4+2+1=7 Matches are Played.
Note: Here in question they asked total matches played .. so answer is 7
if they asked .. how many matches winner played means....then the answer is 3 .

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Balu Ramchandra Misal  (9 years ago)

there are 8 team out of that each team play with other means total 4 match played
out of 4 team 2 match played this 2 team play 1 final match so total no. of match is 4+2+1=7

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Manish  (9 years ago)

Answer is 7 because 8 teams play 4 matches
The wining 4 teams will play 2 matches
then remaining 2 teams will play 1 match , so the total number of matches will be 7.

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rajesh kumar  (7 years ago)

you can take it like this
all team having number a,b,c,d,e,f,g,h
from last a match organised then winner will play with next one
g match h----winner g
g match f -----winner f(such like this )
at the end of 7th match you will get winner
so ans is--------7

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