Latest TCS Aptitude Question SOLUTION: George does 3/5th of a piece of work in 9 days.He then calls in Paul and they finish the work in 4 days.How long would Paul take to do the work by himself?

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George does 3/5th of a piece of work in 9 days.He then calls in Paul and they finish the work in 4 days.How long would Paul take to do the work by himself?

Asked In TCS sanat maity (9 years ago)

Solved nikhil Read Solution (6)

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nikhil  (9 years ago) Best Solution

9day 3/5
1 day 1/15
remaing 1-3/5=2/5
both can do 2/5 work in 4 day
one day work of both=1/10
therfor paul would take 1/10-1/15=1/30 or 30 days

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Simranjit Singh  (9 years ago)

Let the time taken by George be x days

Then the time taken by them to do a work jointly= 15*x/(15+x)

Now 2/5 of the work is left which is completed in 4 days

So [15*x/(x+15)]*(2/5)=4

=>15*x/(x+15)=10

=>15x=10x+150

=>5x=150

=>x=30
So 30 days would be required by Paul to do the work himself.

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mayank arora  (9 years ago)

george does 3/5th work in 9 days,so total days needed by him =15 days
remaining work=2/5
so equation is 1/15+1/x=1/4(2/5)
where x=time taken by pauli.e.30 days

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srinivas  (9 years ago)

3/5 in 9 days
2/5 in 6 days for george
but 2/5 in 4 days
paul can do it in 2/5 in 12 days(1/6+1/p=1/4 then 12 days)
so 3/5 work is 18 days
total 12+18=30

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krishnendu sen  (9 years ago)

ans: 60/11
george does 3/5 of a piece of work in 9 days.

he finish his work in 9*5/3=15 days.

let , paul take x days to finish his work.

so they finish together in (15*x)/15+x = 4

=> x=60/11 days

Is this solution Helpfull? Yes (2) | No (9)  

priya nirwan   (9 years ago)

9 days = 3/5
1 day= 1/15
3/5 work is done, remainin work= 2/5
work done by george in next 4 days = 4/15
by paul= 2/5-4/15
=2/15 wich is work of 4 days.
1 day work= 1/30
so,total days required=30

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