Latest Accenture Aptitude Question SOLUTION: Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is: A. 9 B. 11 C. 13 D. 15

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Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

A. 9 B. 11
C. 13 D. 15

Asked In Accenture (12 years ago)

Unsolved Read Solution (7)

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anil kumar  (11 years ago)

Let numbers are n,n+2,n+4
now 3n=2(n+4)+3
3n-2n=11
so
n=11 then consecutive odd numbers are 11,13,15

Is this solution Helpfull? Yes (10) | No (7)  

Shiv Kumar  (12 years ago)

ANS. D

from the given answers the possible three consecutive odd integers to consider to satisfy the condition are
1) 5, 7, 9
2) 7, 9, 11
3) 9, 11, 13
4) 11, 13, 15

Only the option 4 satisfies Three times the first odd integers is 3 more than twice the third.
Hence the third integer is 15

Is this solution Helpfull? Yes (7) | No (5)  

Mainak Bhaumik  (10 years ago)

ans 9
2x+1, 2x+3, 2x+5 are the tree nos.
3* 2x+1 + 3= 2 * 2x+5
x=2
ans 9

Is this solution Helpfull? Yes (6) | No (3)  

indrajit haldar  (8 years ago)

Answer: Option D

Explanation:

Let the three integers be x, x + 2 and x + 4.

Then, 3x = 2(x + 4) + 3 x = 11.

Third integer = x + 4 = 15.

Is this solution Helpfull? Yes (3) | No (1)  

Sushmita Nath  (7 years ago)

Three integers x,x+2,x+4
3x=3+2(x+4)
3x=3+2x+8
x=11
Therefore 3rd integer is: x+4=11+4=15

Is this solution Helpfull? Yes (3) | No   

Monika  (5 years ago)

Three consecutive odd numbers
2x+1,2x+3,2x+5

3(2x+1) = 2(2x+5) + 3
Slove this,
X=5
Third num is 2(5)+5=15

Is this solution Helpfull? Yes (1) | No   

vishal  (5 years ago)

let numbers are x+1,x+3,x+5
3(x+1)=3+2(X+5)
X=10
SO,
11,13,15 are the numbers.

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