Latest TCS Aptitude Question SOLUTION: the price of a commodity(in rupees per kilogram) is 100+0.1n, on the nthvday of 2007(n=1,2,,,,,100), and then remains constant. On the other hand, the price of another commodity is

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the price of a commodity(in rupees per kilogram) is 100+0.1n, on the nthvday of 2007(n=1,2,,,,,100), and then remains constant. On the other hand, the price of another commodity is 89+0.15n on the nth day of 2007(n=1,2,,,,,,365). On which date in 2007, will the price of these twocommodities be equal????




ans:- may 20

Asked In TCS shubhank` (9 years ago)

Solved Deepak Read Solution (3)

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Deepak  (9 years ago) Best Solution

price of both the commodity cannot be same within 100days( by puttng n=100 in both the price)
price of 1st commodity after 100 days =100+0.1*100= 110
day on which 2nd commodity becomes equal to 1st= 89+0.15n=110
n=140
140th day of 2007 is 20th may ANS

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Ashit Kumar  (9 years ago)

Price of commodity 1 -(100+0.1n)
Here n range is from (1-100)
Also Price of commodity 2- (89+0.15n)
lets check for n==100
if commodity 2 price> commodity 1
then n100
commodity1(n=100) = 110
commodity2(n-100) = 104

Hence price of these 2 commodities will be equal after n=100
Therefore price of commodity 1 will be constant at 100

hence just solve commodity 2 equation by equating to price of commodity 1 at n=100 i.e 110
89+0.15n=110
n=21/0.15
140.

Now Jan=31, Feb=28 , Mar=31 , Apr=30, May=20
31+28+31+30+20 = 140

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vishwanath kumar  (9 years ago)

simple its 20

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