Latest TCS Aptitude Question SOLUTION: Two vehicles A and B leave from Y to X. A overtakes B at 10:30 am and reaches X at 12:00. It waits for two hours and returns to Y. On its way, it meets B at 3 PM and reaches Y at

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(#M40040243) TCS Numerical Ability question Time distance and speed Keep an EYE

Two vehicles A and B leave from Y to X. A overtakes B at 10:30 am and reaches X at 12:00. It waits for two hours and returns to Y. On its way, it meets B at 3 PM and reaches Y at 5 PM. B reaches city X waits for 1 hour and returns to y After how many hours will B reach to Y from the time A overtook him.

Asked In TCS mamta garkoti (9 years ago)

Solved Anuj Yadav Read Solution (10)

Is this Puzzle helpful?   (18)   (4) Submit Your Solution Time Distance and Speed

Read Solution (10) :

Anuj Yadav  (9 years ago) Best Solution

Let distance between A and B be d.
A reaches X at 12:00 waits for 2 hrs and return to Y at 5pm.
Hence speed=dist/time=d/3.....(1)


Now during Y to X he overtakes B at 10:30 and reaches X at 12:00.
Its takes 3 hrs to complete whole distance then in 1:30hrs he should complete Half the distance.

therefore distance from Here to X will be d/2.

Again in return journey he meets B at 3:00 so distance covered should be 1/3

Here distance from X to here is d/3.

Therefore distance covered by B is d/3-d/2=d/6.
Time taken=4.5 hrs

So B will cover distance d in 4.5*6=27hrs.

after meet to A 1st time ,B covers total distance=a/2+a(wait at X)
so total time =27(from X to Y)+27/2(after meeting A 1st time to reach at X)+1(halt at X)=41.5

Therefore answer is 41.5hrs

Explaination:

|--------------------d------------------------------|
Y---------------------------------------------------X
10:30 3:00
|-----d/3--------|
|-------------------||----------d/2------------------|
|--------S-----|

S=d/3-d/2=d/6 in 4.5hrs

Is this solution Helpfull? Yes (48) | No (5)  

Shivam  (9 years ago)

Let the distance between City X and Y be D
As given - B leaves City X at 2:00 (12:00 + 2 hrs halt) and reaches City Y at 5:00

So it takes him 3 hours to cover distance D.

Now, A overtakes B at 10:30 and reaches city Y at 12:00 pm , which means that A traveled for 1:30 hr.

Now see,
A takes 3 hrs takes to cover distance D
so in 1.5 hrs A will cover D / 2 distance

Now see another part -
"On its way, it meets B at 3 PM and reaches Y at 5 PM."
Given that - B leaves City Y at 2 PM
So distance covered by A in 1 hr (3 - 2) = D / 3

Now Total Distance covered by B during (A overtaking B + A wait for two hour + A on its way back ) is

D / 2 [when they first overtake] - D / 3 [when they again overtake]
= D / 6

Now Time elapsed during this period (A overtaking B + A wait for two hour + A on its way back )
=1.5 + 2 + 1
=4.5

so to cover D / 6 distance B took 4.5 hr
to cover D distance B will take (4.5 * 6)
= 27 hr.

Now "After how many hours will B reach to Y from the time A overtook him."
Time to reach X after A overtook (D / 2) + wait + Time to reach Y from X (D)
= 13.5 + 1 + 27
= 41.5

Is this solution Helpfull? Yes (21) | No (1)  

sheela kumari singh  (9 years ago)

ans is 41.5hrs... please refer to tcs seesame

Is this solution Helpfull? Yes (2) | No   

khh  (9 years ago)

35 hours..
??? not sure!!

Is this solution Helpfull? Yes | No (4)  

Sachin Yadav  (9 years ago)

5.5 hr because B also wait for an hour at X

Is this solution Helpfull? Yes | No (2)  

Sachin Yadav  (9 years ago)

5.5 hr because B also wait for an hour at X

Is this solution Helpfull? Yes | No (1)  

Kethineni Vinodh  (9 years ago)

tcs ans 41.5 hours

Is this solution Helpfull? Yes | No (1)  

ddgf  (9 years ago)

ANUJ YADAV how it is comming "Therefore distance covered by B is d/3-d/2=d/6.
Time taken=4.5 hrs" plz xplain

Is this solution Helpfull? Yes | No   

Tamal Chakraborty  (9 years ago)

35 ??
pls correct me

Is this solution Helpfull? Yes | No   

devanshu  (9 years ago)

ans 40.5

Is this solution Helpfull? Yes | No   

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