Latest Accenture Aptitude Question SOLUTION: Q. The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: Option A. 74 B. 94 C. 184 D. 364

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Q. The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:

Option
A. 74
B. 94
C. 184
D. 364

Asked In Accenture (12 years ago)

Solved Dr.Dipin Singh Read Solution (5)

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Read Solution (5) :

Dr.Dipin Singh  (12 years ago)

D. 364

LCM of 6, 9, 15 and 18 is 90.
90*1+4 = 94 not divisible by 7.
90*2+4 = 184 not divisible by 7.
90*3+4 = 274 not divisible by 7.
90*4+4 = 364 is divisible by 7.

so 364 .. option D

Is this solution Helpfull? Yes (20) | No (2)  

prashanthi  (11 years ago)

when divided by 7 it leaves the remainder 4 so n-4 should be the multiple of lcm(6,9,15,18)
So lcm(6, 9, 15, 18) = 2 * 3^2 * 5 = 90.

So n - 4 must be a multiple of 90.

If n - 4 = 0, then n = 4, which doesn't work because 4 isn't a multiple of 7.
If n - 4 = 90, then n = 94, which doesn't work because 94 isn't a multiple of 7.
If n - 4 = 180, then n = 184, which doesn't work because 184 isn't a multiple of 7.
If n - 4 = 270, then n = 274, which doesn't work because 274 isn't a multiple of 7.
If n - 4 = 360, then n = 364. This is a multiple of 7, and so it's the smallest number that works.

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ashish pandey  (11 years ago)

lcm of 6,9,15 and 18 is 90
least multiple of 7 and remainder 4 takes the form 90k+4 which should be divisible by 7. putting k = 4, answer is 364

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anil kumar  (11 years ago)

after LCM of 6,9,15,18 we get 90 but rem is 4 then number can be 90+4=94 but it is not divisible by 7 so
same 74,94,184 are not divisible by 7 ie multiple of 7 is only 364
so Option :D

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alpa sharma  (7 years ago)

LCM OF (6,9,15,18) = 90

90K+4 SHOULD BE DIVISIBLE BY 7
FOR K=4 , 364
DIVISIBLE BY 7

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