Latest TCS Aptitude Question SOLUTION: In a year N, the 259th day of the year is a Saturday. In the year N+l, the 222th day of the year is also a Saturday. What is the 119th day of the year N-l? a) Thursday b) Saturd

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In a year N, the 259th day of the year is a Saturday. In the year N+l, the 222th day of the year is also a Saturday. What is the 119th day of the year N-l?
a) Thursday
b) Saturday
c) Friday
d) Tuesday

Asked In TCS purva (9 years ago)

Solved Dulika Indu Read Solution (7)

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Read Solution (7) :

Abhijit Das  (9 years ago)

as 259th day of year N and 222th day of year N+1 is same i.e saturday, so number of day between above 2 day is must be divided by 7..
no. of days btwn dis 2 day may b (366-259)+222=329----(1) or (365-259)+222=328------(2)
as 329 is divided by 7 so year N is leap year son Year N-1 is not a leap year....
now number of day btwn 119th of N-1 and 259th of N is (365-119)+259 =505
now 505/7 gives remainder 1 , so 504 is divided by 7, so 120th day of N-1 is saturday...so 119th day of N-1 is Friday

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ARCHIE GUPTA  (9 years ago)

N yr 259th Saturdayy = 365-259=106 remaining days
N+1 222nd Saturday 106+222=328 dayss
to determine day which of week =
328%7=6
ie 6 = fridayy
c is correct

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Dulika Indu  (9 years ago) Best Solution

c) Friday
Year n-1 starts on saturday and ends on sunday. So 119th day is a friday

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sourabh shrma  (9 years ago)

ans is friday ...year n+1 is leap year...because 259-222= 37
it means from year n to n-1 thr is diff of 2 days ...if it is ordnry year thn diff will be 1 day bt its leap year thrfr diff is 2 days..

259 is satrday 259-119 = 140 it will be friday...........

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kaushal.arj.02@gmail.com  (9 years ago)

If we consider leap year then it may be Friday also. and if not then it is thursday

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Piyush Kumar  (9 years ago)

n-1 means it is friday because n is given here saturday

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aastha rathour  (8 years ago)

Take the Nth year. In the Nth year 259th is a Saturday.
In the N+1 the year, 222 nd day is also Saturday.
So there must be 0 odd days between these days.
And we don’t have any information, whether Nth year is leap or not.
Case 1 : Let us assume Nth is an ordinary year
Then number of days between these 2 days => (366 - 259) +222 = 328 days
In 328 days, we have 1 odd day . So we can say that N th year is not an ordinary year.
Case 1 : Let us take Nth year is leap,
Number of days between these 2 days => (366 - 259 ) = 329 days
In 329 days ,we have 0 odd day . So we can say that N th year is leap year
As Nth year is leap , N-1 th year is not a leap year.
Number of days between 259 th day of Nth year and 119 th day of N-1 th year
= 259 + (365-119)
= 505 days
The number of odd days in 505 days =>1 odd day
Therefore , 119th day of the year N-1 => Saturday -1 = Friday

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