Latest TCS Aptitude Question SOLUTION: A ladder 100 feet long is leaning against a vertical wall Its lower end is 60 foot from the bottom of the wall The side of the largest cubical box that can be placed between the

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(#M40040721) TCS Numerical Ability question Keep an EYE

A ladder 100 feet long is leaning against a vertical wall Its lower end is 60 foot from the bottom of the wall The side of the largest cubical box that can be placed between the wall and the ladder without disturbing the ladder is (to the nearest foot).
a) 26 b) 34 c) 21 d) 40

Asked In TCS purva (9 years ago)

Solved ANJALI AGARWAL Read Solution (16)

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kaushal.arj.02@gmail.com  (9 years ago)

It should be 34...?

Is this solution Helpfull? Yes (13) | No (2)  

ANIMESH GORAI  (9 years ago)

the answer may be 34.2
if we consider the 2d image then the ladder , the wall and base making a triangle ,which height =80 foot
now we have to calculate the largest square inside the triangle.
let x be the side of square.
then,there are two triange of one height=x ,base=(60-x) and the other of height=(80-x) and base=x and a squre
by condition
(60-x)*x/2+x*(80-x)/2+x^2=80*60/2
x=34.2
am i correct?

Is this solution Helpfull? Yes (12) | No (1)  

sindhu  (9 years ago)

Let the angle between ladder and Horizontal be A, and side of cuboid be s
First find the wall height i.e, 80ft (because we need to find tanA)
tanA=80/60=4/3.........(1)
Now, tanA=s/60-s
4/3=s/60-s
s=34.2

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EKTA PATIL  (9 years ago)

we can calculate the height of the given triangle,which is formed by the wall and ladder,USING PYTHAGORUS theorem as....
height=(100^2)-(60^2)= 80

now as the cube will be having one of its vertices on the wall..and another one on the Ladder.So Logically,the longest edge of such cube will be obtained only by a line joining the mid points of wall as well as ladder. so as mid point of wall is 80/2 = 40..so side of the resultant cube will be 40!!

i hope u will understand this after reading it twice or thrice ..use a diagram also.

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ANJALI AGARWAL  (9 years ago) Best Solution

using pythagorus..ans will b 40

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Rajnandini Sharma  (9 years ago)

Kaushal can you explain it

Is this solution Helpfull? Yes (3) | No (1)  

Ashish singh  (8 years ago)

by using pythagoras theorem we get height = 80, now the largest cube that can be placed inside the triangle must have side = hb/(h+b)
we get 4800/140 =34.2
....where h is the height of triangle and b is the base.

Is this solution Helpfull? Yes (3) | No   

Abir chakraborty  (9 years ago)

it is dummy question asked in tcs. do not attempt such question because the answer should be 49m. and it is not in options. Attempting such questions will suggest that you are guessing and you are liable to rejection.

Is this solution Helpfull? Yes (2) | No (5)  

Vaibhav Randhai  (9 years ago)

34 Is d ans

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nikhilangelina@gmail.com  (8 years ago)

bhai tumhe admin kisne bna diya ...............iska ans 40 h...

60/x=80/80-x= 34.2

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priya  (7 years ago)

60^2+40^2=100^2
so ans is 40...........

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Narasapu Hari prasad  (9 years ago)

ans is 40

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sourav kumar  (9 years ago)

It Should be 40

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Aparna S M  (9 years ago)

can any please explain how 40 is the right answer????

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Harsh Vyas  (9 years ago)

Pls provide explaination

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Abhishek nkumar  (8 years ago)

we can calculate the height of the given triangle,which is formed by the wall and ladder,USING PYTHAGORUS theorem as....
height=(100^2)-(60^2)= 80
now the largest cube that can be placed inside the triangle must have side = hb/(h+b)
we get 4800/140 =34.2
where h is the height of triangle and b is the base.

Is this solution Helpfull? Yes | No   

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