Latest TCS Aptitude Question SOLUTION: Find the number of ways in which one or more letter be selected from the letters AAAABBCCCDEF. A. 479 B. 480 C. 958 D. 960

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(#M40041234) TCS Numerical Ability question xplain the answer Keep an EYE

Find the number of ways in which one or more letter be selected from the letters AAAABBCCCDEF.
A. 479
B. 480
C. 958
D. 960

Asked In TCS piyush joshi (9 years ago)

Unsolved Read Solution (4)

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Read Solution (4) :

nisha sharma  (9 years ago)

As A occurs 4 times, we can choose A in 4+1 ways

So, the number of ways of selection of no or more letters from the word:
AAAABBCCCDEF will be N=(4+1)(2+1)(3+1)(1+1)(1+1)(1+1)
Clearly, this contains one combination of choosing no letter

So, the number of ways of selection of one or more letters will be N−1
ans=480-1=479 (A)

Is this solution Helpfull? Yes (40) | No (2)  

shrestha gadi  (9 years ago)

((4+1)(2+1)(3+1)(1+1)(1+1)(1+1))-1 = 479

Is this solution Helpfull? Yes (5) | No (2)  

tejasvita  (9 years ago)

2^12-1/4!3!2!
why it is wrong?

Is this solution Helpfull? Yes (1) | No (3)  

Aryan  (9 years ago)

@TEJASVITA nice interpretation but u are considering 2^12 for every number two possibilities , we are not taking factorial eg 2^4=8 only to divide it should be 4!=24.hope it vl clear ur doubt little bit.

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