Latest TCS Aptitude Question SOLUTION: Jake can dig a well in 16 days. Paul can dig the same well in 24 days. Jake, Paul and Hari together dig the well in 8 days. Hari alone can dig the well in a. 96 days b. 48 days

jake 1 day work=1/16
paul 1 day work=1/24
j+p+h 1 ady work=1/8
1/16+1/24+1/x=1/8
1/x=1/48
x=48
so,Hari alone can dig the well in 48 days

ANS IS :48
LCM OF 16,24=48
TOTAL UNIT WORK IS=48
JAKE=48/16=3
PAUL=48/24=2
JAKE+PAUL+HARI=48/8=6
3+2+HARI=6
5+HARI=6
HARI=1
HARI ALONE CAN DIG THE WELL IN 48/1=48 DAYS

let us assume that x be the days taken by hari.jake can done in 1/16,paul can done in 1/24,
J+P+H=1/8
1/16+1/24+1/x=1/8 then by solving we get x=48

Simple one. Let the total work to be done is 48 meters. Now Jake can dig 3 mts, Paul can dig 2 mts a day. Now all of them combined dug in 8 days so per day they dug 48/8 = 6 mts. So Of these 8 mts, Hari capacity is 1 mt.
So he takes 48 /1 = 48 days to complete the digging job.

hari=1/8-(1/16+1/24)=1/8-5/48=6-5/48=1/48
48 days he can do.

1/16+1/24+1/h=1/8
h=48

simple find lcm of 24,16,8 find one day work and then find
and simple 48 days

let it be x days for Hari to complete the task
=> (1/x) = (1/8) - (1/16) - (1/24)
=> (1/x) = (1/48)
reciprocating the values x= 48
So, Hari alone can complete in 48 days

32
hklkjl

ans-32
40-8=32

hari=(1/8-1/16-1/24)
= 48

48
total work done by jake,paul,hari=1/8
work done by hari=1/8-1/16-1/24=1/48
hari can dig in=48 days

(b)
one day work of jake is 1/16
one day work of jake is 1/24
one day work of jake is 1/x
1/16+1/24+1/x=1/8
x=48 days

48 days
1/8-(1/16+1/24)=1/48
so 48 days taken by hari to dig it

48/5 days

48days
1/8-(1/16+1/24)

48 is right

j+p+h=1/8
h=(1/8)-(1/16)-(1/24)
h=1/48
so 48 days

l.c.m of(16,24)=48
j per day=48/16=3unit
p per day=48/24=2unit
j+p+h 1day=48/8=6 unit
so h=6-(3+2)=1unit per day
so total work=48day

j+p+h=8
j+p=(j*p/j+p)=9.6
1day for j+p+h=1/8
1day for j+p=1/9.6
1 day for h=1/8-1/9.6=1/48
48 days

j+p+H=1/8
h=1/8-1/16-1/24
h=1/48
48days

1/8-(1/16+1/24) =1/8 - (5/48) =48ans

j =16 days
p =24 days
j+p+h =8 days
total work=48 unit
j can do =3 unit/day
p can do=2 unit/day
j+p+h can do=6 unit/day
h=1 unit/day
h takes 48 day to complete

b. 1-(1/2+1/3)=1/6. 1/6th part of work is done by hari so 6x8 = 48 days for alone hari to work.

3.48 days.
1/8-(1/16+1/24)=1/48
=48 days.

Let the total work to be done is 48 meters.
Now Jake can dig 3 mts, Paul can dig 2 mts a day.
Now all of them combined dug in 8 days so per day they dug 48/8 = 6 mts.
So Of these 8 mts, Hari capacity is 1 mt.
So he takes 48 /1 = 48 days to complete the digging job.

j->16 3
p->24 48 2
j+p+h->8 6
hari->6-5=1
1*48=48 days

Let the total work to be done is 48 meters.
Now Jake can dig 3 mts, Paul can dig 2 mts a day.
Now all of them combined dug in 8 days so per day they dug 48/8 = 6 mts.
So Of these 8 mts, Hari capacity is 1 mt.
So he takes 48 /1 = 48 days to complete the digging job.