Latest L&T Aptitude Question SOLUTION: 27. A hawker purchased oranges at the rate of 4 oranges in a rupee, but he sells at the rate of 5 oranges in a rupee. His loss is: (a) 20% (b) 25% (c) 50% (d) 100%

• Placement Papers
• /
• L&T
• /
• Numerical Ability
• /
• Profit and Loss

L&T Question Papers: L&T Company Profile

(#M40041324) L&T Numerical Ability question Keep an EYE

27. A hawker purchased oranges at the rate of 4 oranges in a rupee, but he sells at the rate of 5 oranges in a rupee. His loss is:
(a) 20%
(b) 25%
(c) 50%
(d) 100%

Asked In L&T Jayesh Hazari (9 years ago)

Unsolved Read Solution (11)

Is this Puzzle helpful?   (75)   (30) Submit Your Solution Profit and Loss

Read Solution (11) :

Chirag Ranjan Lahiri  (9 years ago)

loss percentage =
((buying price - selling price)/buying price)*100
so it is 20%

Is this solution Helpfull? Yes (10) | No (9)  

pushpank thakur  (8 years ago)

cp of 4 oranges= Rs. 1
sp of 5 oranges = Rs, 1
SP of 1 orange = 1/5 = 0.2 rupee
SP of 4 oranges = 4 * 0.2 = 0.8 rupee
% loss = [(CP - SP)/CP]*100
= [(1-0.8)/0.8]*100
= [0.2/0.8]*100
= [1/4]*/100
=25%

Is this solution Helpfull? Yes (8) | No (11)  

THUMMALA VINEESHA  (8 years ago)

loss%=[(cp-sp)/cp]*100
=[(1/4-1/5)/1/4]100
=(1/20)*4*100=20%

Is this solution Helpfull? Yes (7) | No (1)  

k vydehi  (9 years ago)

loss=(1/4-1/5)/(1/4)*100=20%

Is this solution Helpfull? Yes (6) | No (4)  

Shyam Kumar  (7 years ago)

Let cost price of 4 oranges= Rs.100, cost[price of 1 orange is =25
Let selling price of 5 oranges =Rs.100, selling price of 1 orange is = 20
s0, Loss= (Cost price of 1 Orange - Selling price of 1 orange)=25-20=5
Loss %= (loss/c.p of 1 orange)*100
=(5/25)*100= 20%

Is this solution Helpfull? Yes (6) | No (2)  

tirupathi reddy  (9 years ago)

Option a)20%
C.p of 4 org ---1/-

S.p of 5 org---1/-
Find c.p of 4org
4x= 5(1)
C.p of 4 org is (x)=0.8

Loss = (1-0.8)/1*100 =20%

Is this solution Helpfull? Yes (4) | No (2)  

Arun  (9 years ago)

20%
loss percentage =
((buying price - selling price)/buying price)*100

Is this solution Helpfull? Yes (1) | No   

sheetal  (7 years ago)

400 oranges buys for 100 rupees(4 per rupee) and 400 oranges sells for 80 rupees(400/5=80)
100-80=20
ans=20%

Is this solution Helpfull? Yes (1) | No (2)  

BHARAT KUMAR  (7 years ago)

loss =(25/125)*100=20

Is this solution Helpfull? Yes (1) | No   

sivaraman  (6 years ago)

4c.p=5s.p
s.p/c.p=4/5
loss=1
%=1/5*100=20%

Is this solution Helpfull? Yes | No (1)  

Antony  (6 years ago)

1 rupee = 4 oranges = 25 paisa each
Then for 5 oranges - 20 paisa each

So loss 25-20 = 5 paisa per orange

5/25 * 100 = 20℅

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.