Latest IBM Aptitude Question SOLUTION: 48, 46, 42, 38, ? a)32 b)30 c)33 d)34 e)35

48-42=6,46-38=8,42-32=10
so,ans:32

48-2=46
48-6=42
48-10=38
48-14=34 so answer is 34

alternative series 48-42=6
46-38=8
then next wl b the diiference should b 10 so 42-10=32

ans:b
48-46=2
46-42=4
42-38=6
38- x =8=>x=30

(48-46)*1=2
(46-42)*2=8
(42-38)*3=12
(38-34)*4=16
ans=34

a manufacturing company has 15% cobalt ,25% led and 60% of copper. if 5kg of led is used in a mixture how much copper we need to use
ans
25%=5kg
100%=20kg
60% of 20 kg= 12kg
12 kg.....

A man bought some mangoes at Rs12 per dozen and bought the same number of at Rs
10 per kg. He sold these mangoes at Rs 13 per dozen and gained Rs 160.The total
number of mangos bought by him are
Option
A. 60 dozens
B. 70 dozens
C. 80 dozens
D. 90 dozens
ans
let total no of mangoes is 2x..
then we profit=sp-cp
160=13*2x-(12x+10x)
160=4x
x=40
hence 2x=80
so total no are 80dozens
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in a bus left side are 15 seats available,3 few seats in right side because in rear
exit door .Each seat hold 3 people.In addition ,there is a seat back can sit 7 people
all together .how many people can sit in a bus?
options:
a)52 b)49 c)95 d)88 e)66 pls explain
ans
Right Side =15 seat
Left Side =15-3 (3 few seat in right side)= 12 seat
Total= 15+12= 27
People can seat in 27 seat= 27*3=81
People can seat in Last Seat = 7
Total People can seat= 81+7=88
Ans= d) 88
Three numbers A,B,Care in ratio 1:2:3. Their average is 600. If A is increased by
10% and B is increased by 20%, then to get the average increased by 5%, C will increased by:
a)90
b)100
c)150
d)180
ans
Let be A= x, B=2x, and C=3x.
(x+2x+3x)/3=600
this will be x=300
so, the numbers will be 300,600,900
new average= 105%of 600= 630
Let 110% of 300+80% of 600 + y= 630*3
solve it for y, you will get, y=1080
so, increase in C= 1080-900 =180 ans
=========================
A and B together can complete a work in 12 days. A alone can complete it in 20 days.
If B does the work only for half a day daily, then in how many days A and B together
will complete the work?
A. 10 days B. 11 days
C. 15 days D. 20 days
ans
see ,
here given that A and B can do the work in 12 days
so A+B 1 day work = 1/12 unit.................................(1)
also given that , a alone can finish the work in 20 days
therefore
A 1 day work = 1/20 unit........................................(2)
using 1 and 2
we get,
B's 1 day work =1/12 - 1/20
=1/30..............................(3)
---> b can do the complete work in 30 days
now according to statement
if b does the work only half a day then it takes double days (i.e. 60) to complete the work
so now B 1 day work = 1/60.
also we know
A 1 day work = 1/20
now,
A+B 1 day work = 1/60 + 1/20
= 4/60
= 1/15 unit work
hence ,
A and B together will complete the work in " 15 DAYS " (answer)
10 women can complete a work in 7 days and 10 children take 14 days to complete the work.
How many days will 5 women and 10 children take to complete the work?
A. 1 B. 3
C. 5 D. 7
ans
5 women's 1 day work=1/14
ans= 1/14 + 1/14
= 1/7 units of work
so 7 days
===============================
15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each
would 21 women take, if 3 women do as much work as 2 men ?
ans
15*21*8=2520 man hrs
3w=2men,
1 w=2/3 men,
6d*21*2/3=2520
d=30days
@@@
formula D = M*D*H/M*H

so Days = 15*21*8/14*6 = 30 Days
===========================================
Q. A certain number of bullets were shared by 3 people equally.Each of them fired 4 bullets
and the sum of the remaining bullets was equal to the initial share each had got. What was
the initial number of bullets?
Ans
lets each one got x bullets .
so total no of bullets= 3x.
a/c to question each person used 4 bullets each one has remains with x-4 bullets.
so (x-4)3=x.
x=6.
so total no of bullets =3x =3*6 =18
60 litres of diesel is required to travel 600 km using a 800 cc engine.
If the volume of diesel required to cover a distance varies directly as
the capacity of the engine, then how many litres of diesel is required to
travel 800 kms using 1200 cc engine?
Ans
let keep 800 cc constant and calculate amount of diesel for 800 kms.
800*60/600=80 liters.
Now, calculate diesel required for new distance i.e 800 km,
80*1200/800=120 liters.
If a man walks at rate of 5 kmph, he misses a train by 7 minutes. However, if
he walks at rate of 6 kmph,he reaches the station 5 minutes before the arrival
of train. Find the distance covered by him to reach the station. [IET] 1)8 km
2)6.5 km 3)6 km 4)7 km
Ans
guys there is a simple frmula for such kind of questions where time interval matters
(S1*S2)/(S2-S1)* time interval
for example
(6*5)(6-5)*(12/60)
so ans will be 6km .
==============================
Prints a page 64 pg per min .If the printed for 3 hours except 10 min.Where there
was an paper jam,how many page did it print
Options:
a)11,700 b)2860 c)11,684 d)12,140 e)10,600
a person travels from his house to office from 11:10am to 11:50 am and covers a distence
of 13.4km. find the average speed of the person.
Ans
time = 11:10 am to 11:50 am = 40 min = 40/60 =2/3 hr
distance = 13.4 km
avg speed = 13.4 /2/3 = 20.3 km/hr
A company has offices in two different buildings. 50% of the copying machines in the first building and 28% of the copying machines in the second building received preventive maintenance last
month. If 87% of the company’s copying machines are in the first building, what percent of all thecopying machines received preventive maintenance last month?
Ans
50% of 87 machines is 50*87/100=43.5 and
28% of 13 machines is 13*28/100=3.64,
So
43.5+3.64 =47.14
A company organzied a help desk.there have been done 24 hrs work on software,17 hrs
on help user nd 40% on other services.find the total no. of hrs have been worked on
that day?
Ans
let total no of hrs = x
they have done 24+17=41
40% of x is 40/100=2/5
x=41+2x/5
x=68.3
A company rented a machine for Rs.700/- a month. Five years later the treasurer calculated
that if the company had purchased the machine and paid Rs.100/- monthly maintenance charge,
the company would have saved Rs.2000/-. What was the purchase price of the machine?
Ans
Let the price of the machine = x rupee
5 year maintenance charge = 100*60 = 6000
so total investment = x+6000
now total rental charges for five year = 700*60 = 42000
so according to give

30 the difference between two consecutive numbers goes on incresing by 2