Latest HCL Aptitude Question SOLUTION: If the sum of two numbers is 55 and the H.C.F. and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: Option 1 : 55/601

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(#M40051336) HCL Numerical Ability question Keep an EYE

If the sum of two numbers is 55 and the H.C.F. and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:

Option 1 : 55/601 Option 2 : 601/55 Option 3 : 11/120 Option 4 : 120/11

Asked In HCL Manas Nanda (9 years ago)

Unsolved Read Solution (7)

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Read Solution (7) :

Shaik Aarif Mohammed  (9 years ago)

given a+b=55,hcm and lcm is 5 and 120
axb=lcmx hcf
600=120x5
1/a+1/b=a+b/ab=>55/600=>11/120

Is this solution Helpfull? Yes (34) | No   

dhivya  (9 years ago)

is there any criteria for direct interiew in hcl for 2015 passouts?

Is this solution Helpfull? Yes (3) | No (4)  

Akanksha Swarup  (9 years ago)

option c) 1/a+1/b=(b+a)/ab=55/600=11/120

Is this solution Helpfull? Yes (1) | No   

Rashmi Rekha Biswal  (8 years ago)

Ans: option 3

Suppose sum of of num a+b=55
given dat H.C.F and L.C.M of these num are 5 and 120 dat is equal to product of two num means
ab=5*120=600
So sum of reciprocals of the numbers i.e1/a+1/b =a+b/ab
=55/600
=11/120

Is this solution Helpfull? Yes (1) | No   

Vishwas Nahar  (9 years ago)

15 40
5*3 2*2*2*5
LCM
5*2^3*3=120

1/15+1/40
=11/120

Is this solution Helpfull? Yes | No   

Ashwini  (9 years ago)

given: (x+y)=55 .lcm=120 , hcf=5
let the two no: be x & y.
the reciprocal of the no: is 1/x & 1/y.
we know that
num1* num2=lcm*hcf
x*y=120*5=600
ques is sum of reciprocal of given no
therefore we have to find 1/x+1/y
(x+y)/xy=55/600=11/120

Is this solution Helpfull? Yes | No   

sudha singh  (9 years ago)

a+b=55
hcf=5
lcm=120
product(ab)= lcm*hcf=120*5=600
1/a + 1/b =(a+b)/ab =55/600 = 11/120

Is this solution Helpfull? Yes | No (1)  

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