Latest Elitmus Aptitude Question SOLUTION: Soldiers were practicing to shoot. Coincidence occurred, first soldier shoot the target in his first chance, second shoot the target in his 3rd chance (i.e. 1 +2), t

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(#M40053876) ELITMUS Numerical Ability question Keep an EYE

Soldiers were practicing to shoot. Coincidence occurred, first soldier shoot the target in his first chance, second shoot the target in his 3rd
chance (i.e. 1 +2), third shoot in his 6th chance (i.e. 1+2+3), and so on. Total 9880 bullet were fired. Find the number of soldier.

Asked In Elitmus Vaibhav Sharma (9 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

Mithun Kumar Kesari  (9 years ago)

given
1st soldier fired 1 bullet,
2nd soldier fired 2 bullets,
3rd soldier fired 6 bullets,
------
so nth soldier fired {n*(n+1)/2} bullets.

it forms a series like
1+3+6+----+Tn
Where Tn is the nth term of the series

so Tn= {n*(n+1)/2}

and sum= sigma[Tn]={n*(n+1)*(n+2)}/6

given total bullets fired = 9880

so, sum=9880

{n*(n+1)*(n+2)}/6=9880

solving this we get n= 38

so, no. of soldiers =38.

Is this solution Helpfull? Yes (16) | No (1)  

Mithun Kumar Kesari  (9 years ago)

@Dipankar Dey,,,, In Elitmus question paper there are options.. so you have to do only check by opp for such type of questions.

Is this solution Helpfull? Yes (7) | No   

Ajay Singh  (9 years ago)

Ans=38

1+3+6+10+15+21+28+36+...........= [N(N+1)(N+2) ] / 6

PUT N=38

Is this solution Helpfull? Yes (4) | No (2)  

ANANT VIKRAM SINGH  (9 years ago)

how n(n+1)(n+2)/6

Is this solution Helpfull? Yes (3) | No   

Ajay Singh  (9 years ago)

Ans=38

1+3+6+10+15+21+28+36+..........N (times) = [N(N+1)(N+2) ] / 6

Where N is the no. of Soldiers

PUT N=38
(38x39x40)/6=9880.

Is this solution Helpfull? Yes (1) | No (1)  

Ajay Singh  (9 years ago)

find the value of N by option which are given.

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maharaja  (9 years ago)

bt my answer is 988.....for 3 soldier ....total...10....shoots....so for 9880 shoot.......988 soldier..

Is this solution Helpfull? Yes (1) | No (3)  

Dipankar Dey  (9 years ago)

how did u find the value of n in last line...

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Chirag Ranjan Lahiri  (9 years ago)

1+3+6+10+15+21+28+36+...........= [N(N+1)(N+2) ] / 6
thus, n = 36...

Is this solution Helpfull? Yes | No (2)  

kamal  (9 years ago)

hhow can we get value of n?

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