Latest Wipro Aptitude Question SOLUTION: The average of 7 consecutive numbers is 33. The largest of these numbers is : a. 36 b. 33 c. 30 d. 28

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The average of 7 consecutive numbers is 33. The largest of these numbers is :

a. 36
b. 33
c. 30
d. 28

Asked In Wipro (12 years ago)

Unsolved Read Solution (17)

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Read Solution (17) :

soujanya  (9 years ago)

the sum of seven consecutive numbers are
x, x+1 ,x+2, x+3, x+4, x+5, x+6


the average is x+x+1+x+2+x+3+x+4+x+5+x+6 / 7 =33
7x+21=231

x=30

the highest value x+6 substitute x value will get 36

Is this solution Helpfull? Yes (10) | No (1)  

Rakesh  (11 years ago)

ans: 7x+21=231
x=30
ans=36

Is this solution Helpfull? Yes (1) | No (3)  

anushiya  (9 years ago)

average=1/2(2a+(n-1)d)
a=starting number
n=count of numbers=7
d=difference between two numbers=1(since consecutive numbers)
average=33
1/2(2a+(7-1)1)=33
1/2(2a+6)=33
2/2(a+3)=33
a+3=33
a=33-3
a=30
7 numbers are 30,31,32,33,34,35,36
ans is 36

Is this solution Helpfull? Yes (1) | No   

Ritika Barethia  (9 years ago)

[Rakesh]
7x+21=231
x=30
ans=36

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hema sree  (9 years ago)

let 7 numbers be x,x+1,x+2,x+3,x+4,x+5,x+6
then avg=33=(7x+21)/7
then x=30
hence largest number is 36.

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Gaurav Singla  (8 years ago)

x+x+1+x+2+x+3+x+4+x+5+x+6=33*7
7x+21=231
7x=210
x=30

largest no. is x=6 i.e. 30+6=36

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J Bharathi  (8 years ago)

X+X+1..........+X+6/7=33
x=30
x+6=36

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Aditi Dandotia  (8 years ago)

Let the consecutive seven numbers be x, x+1, x+2, x+3, x+4, x+5 and x+6.
Then, (x + x+1 + x+2 + x+3 + x+4 + x+5 + x+6) / 7 =33
=> x = 30;
The Largest number will be x+6, so the answer is 36.

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JENSI KARUNYA.S  (8 years ago)

option is:a) 36 is the largest number of the consecutive numbers 30,31,32,33,34,35,36 have the average 33.

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Ankit Kumar Maurya  (7 years ago)

a is the correct option

Is this solution Helpfull? Yes | No (1)  

swathi kiranmai  (7 years ago)

a.36 is the ans.
x+(x+1)+(X+2)+(X+3)+(X+4)+(x+5)+(x+6)=231;

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Harjeet Kaur  (7 years ago)

Take common 4th no. is 33
5th is 34
6th is 35
then 7th no automatically 36

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shaheena  (7 years ago)

let 7 numbers are
a,a+1,a+2,a+3,a+4,a+5,a+6
then sum is a+a+1+a+2+a+3+a+4+a+5+a+6/7=33
7a+21=231
a=30
so answer is c

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dikshant gangawat  (6 years ago)

firstly find mid no 7+1/2=4th term will be avg
so 4th term is 33 ,
5th 34,
6th 35
7th 36 final answer

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manikanta  (6 years ago)

Ans : 36
Let the numbers are: x-3,x-2,x-2,x,x+1,x+2,x+3
so avg of above numbers is x which is equal to 33 (given),
therefor the largest number is x+3 = 33+3 = 36.

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HARIKRISHNA  (6 years ago)

let us assume the middle one as X
then consecutive members are X-3,X-2,X-1,X,X+1,X+2,X+3 respectively
then sum of all =7X
according to question 7x=33*7
x=33
largest number=X+3=33+3=36

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Rajaboina Radhika  (6 years ago)

a.36

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