Latest TCS Aptitude Question SOLUTION: Alok and Bhanu play the following min-max game.Given the expression N=X-Y-Z where X,Y, and Z are variables representing single digits(0 to 9).Alok would like to maximize N while Bh

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Alok and Bhanu play the following min-max game.Given the expression
N=X-Y-Z
where X,Y, and Z are variables representing single digits(0 to 9).Alok would like to maximize N while Bhanu would like to minimize it.Towards this end,Alok chooses a single digit number and Bhanu substitutes this for a variable of her choice(X,Y,Z).Alok then chooses the next value and Bhanu,the variable to substitute the value.Finally alok proposes the value for the remaining variable.Assuming both play to their optimal strategies,the value of N at the end of the game would be

a)9
b)4
c)2
d)-18

Asked In TCS YadeeshKumar (13 years ago)

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armaan  (13 years ago)

it will maximum of 2

Is this solution Helpfull? Yes (7) | No (3)  

digvijay vaghela  (12 years ago)

for this type of ques...remembr that X+Y-Z=11
X-y-Z=2
X*(Y+Z)+18
so above case anser will be2

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shriram  (13 years ago)

a)

Is this solution Helpfull? Yes (1) | No (11)  

Som  (13 years ago)

plz explain in details

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Arghadeep Chaudhury  (13 years ago)

alok want to max N. so he should choose 0 first. bcz other values make N negative for x=y=z. alok selection x=y=z=0. N=0. Then bhanu sub the value of her choice which make N min. N=0-y-z=-y-z. Alok choose next value=1 and N=-1 and bhan's case N become N=1-y-z. The ultime digit alok should choose=9. therefore N=9-9-9=-18.therefore FINAL VALUE of N=-18(d)

Is this solution Helpfull? Yes (1) | No (8)  

Abhishek nkumar  (8 years ago)

X-y-Z=2
X*(Y+Z)+18
so above case Answer is 2

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