Latest TCS Aptitude Question SOLUTION: 5 cards drawn at random one after another from a deck of 52 cards with replacement.The probablity that a spade card occurs at most once is .....

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(#M40083865) TCS Numerical Ability question probablity Keep an EYE

5 cards drawn at random one after another from a deck of 52 cards with replacement.The probablity that a spade card occurs at most once is .....

Asked In TCS Jaspalsingh Parmar (9 years ago)

Unsolved Read Solution (6)

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Read Solution (6) :

ali  (9 years ago)

no of spades = 13
5 cards drawn one after another with replacement
probability of no spade card is = 39/52 * 39/52 *39/52 *39/52 *39/52 = (3/4)^5
probability of one spade is =( 1/4)(3/4)^4 + (1/4)(3/4)^4 + (1/4)(3/4)^4 + (1/4)(3/4)^4 + ( 1/4)(3/4)^4
probabity of a spade cards at most once is = (3/4)^5 + ( 1/4)(3/4)^4 + (1/4)(3/4)^4 + (1/4)(3/4)^4 + (1/4)(3/4)^4 + ( 1/4)(3/4)^4 = 81/128
hence answer is 81/128

Is this solution Helpfull? Yes (11) | No   

Divi   (9 years ago)

Probability of occurring 0 plus once
5c0*(1-13/52)^5+5c1*(13/52)*(1-13/52)^4
We get 81/128

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swetha  (9 years ago)

1/1024
no. of spades = 13
0ut of 52 with replacemnet we can take 13 spades
13 * 13* 13*13*!3
total probability = 52 *52*52*52*52
13*13*13*!3*13/52*52*52*52*52
=1/1024

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Priya Pandey  (9 years ago)

please provide its answer

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raunaque.afroz  (9 years ago)

since 5 cards r drawn 1 by 1 with replacement
so no of possible 13*13*13*13*13
probabability=13*13*13*13*13/52*52*52*52*52=1/1024

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meenakshi maurya  (9 years ago)

ans=.63
(39c4*13c1)/52c5 +(39c5*13c0)/52c5=.6328

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