Latest TCS Aptitude Question SOLUTION: A person run from A to B.He took 1/4 of the time less to reach B when compare to run at normal Speed.Then how many percentage he has increased his speed?

• Placement Papers
• /
• TCS

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40000961) TCS question Keep an EYE

A person run from A to B.He took 1/4 of the time less to reach B when compare to run at normal Speed.Then how many percentage he has increased his speed?

Asked In TCS mAhEsH.A (13 years ago)

Unsolved Read Solution (2)

Is this Puzzle helpful?   (4)   (1) Submit Your Solution

Read Solution (2) :

Gaurav Chakraborty  (13 years ago)

Let the distance be constant = D (A to B)
consider Speed is x.
Thus time = T
Secondly, Distance = D, Speed = x + y , Time= (3/4)T
Thus, D= xT= (x+y)* (3/4)T
or x=3y
implies that previous his speed was 3y and later it becomes 4y.
thus % increase =(4-3)/3 *100% =33.33 % Ans
or D(y)

Is this solution Helpfull? Yes (14) | No   

sajesh  (13 years ago)

let A to B time taken T,
now A to B time taken (T-.25T)
distance D=S*T
by taking distance constant speed is (S+x)
so by taking ratio speed should increase to 33.33%(percentage).

Is this solution Helpfull? Yes (1) | No   

Please Login to Read Solution.