A is 2 years older than B who is thrice as old as C. The total of the ages of A, B and C is 51. What

SAYAN CHATTERJEE   6 years AGO

A=B+2
B=3C
SO, A+B+C=3C+2+3C+C=7C+2=51
=> C=7
SO, B=7*3=21
& A= 21+2=23
SO, A*B*C= 7*21*23=3381
Option 2.

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Sukanya Ray Chowdhury    6 years AGO

3c+2+3c+c=51
c=7
b=21
a=23
abc=23×21×7=3381

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G.S.Kantharao   6 years AGO

Let the ages are (3x+2),(3x),(x)
(3x+2)+(3x)+(x)=7x+2=51
X =(51-2)/7=49/7=7
Their ages are=23,21,7yrs.
Product of their ages=3381yrs.
Hence the right option is 2.

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Poulami Banik   6 years AGO

Let age of C=x
Age of B=3x
Age of A= 3x+2
So,
(3x+2)+3x+x=51
x=7
So C=7,B=21,A=23
Product of their age....
7*21*23=3381

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Mukund Manohar   6 years AGO

Let the age of C be x years
Age of B = 3x years
Age of A = 3x+2 years
ATQ,
3x+2 + 3x + x = 51
=> 7x = 49
x = 7
C = 7 years
B = 21 years
A = 23 years
Product of their ages = 7*21*23 = 3381

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ajit bharti   6 years AGO

Let the age of C,B and A be x,3x,3x+2.
According to question sum of ages equals to 51.
i.e. 7x+2=51.
Therefore x=7.
Now the ages will be.
C=x=7years
B=3x=21years
A=3x+2=23years
So, the product of ages will be 7*21*23=3381

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Gokul Krishnan   6 years AGO

Given c=x,b=3x,a=2+3x
total=51
x=7
hence product is=3381

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Pavleen   6 years AGO

let C age be x. then B age will be 3x and A age 2+3x.the sum of ages of A,B and C is 51.therefore after solving the equation we get all the ages.

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aparna padakanti   6 years AGO

c=c b=3c a=3c+2 a+b+c=51 by solving we get c=7b=21a=23 abc=3381

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Mounika   6 years AGO

A=2+B --------(1)
B=3C ----------(2)
And A+B+C=51 -----(3)
Solving equations (1),(2)&(3) ; we get
A=23, B=21 and C=7

Product of their ages is ABC = 23*21*7=3381

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Vishalakshi Tiwari   6 years AGO

A=B+2,B=3C
A+B+C=51
ON SOLVING,
A=23 Years, B=21 Years, C=7 Years
Hence,
A×B×C=23×21×7=3381

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Nitish Sinha   6 years AGO

Let the age of C be x years,
therefore B=3x and A= 3x+2 years respectively
Now,
(3x+2)+3x+x=51
7x+2=51
x=7
Putting the value x we get,
Age of A= 3x+2=23
Age of B= 3x= 21
Age of C= x=7

Therefore product of their ages are:
23*21*7= 3381
Answer : Option 2

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Deepika   6 years AGO

A=b+2
B=3c
A+b+c=51
B+2+b+b/3=51
3b+6+3b+b=153
7b=147
B=21
C=7
A=23
A*b*c=3381

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sameer   6 years AGO

X+3x+3x+2=51 where we get x=7 so the respective ages are 7,21,23 and their product comes to be 3381

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Harshita   6 years AGO

Let the age of C be x, so age of B=3x and that of A is 3x+2.
so x+3x+3x+2=51
7x+2=51
x=7
so age of C=7,
age of B= 21
age of A= 23
A*B*C=3381.

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prashant   6 years AGO

eqn 1. A=2+B
eqn 2. B=3C
eqn 3. A+B+C=51
putting B=3C from eqn2 in eqn 1,
we get A=2+3C(eqn. 4)
now putting the value of eqn 2 and eqn 4 in eqn 3
We'll get C=7 so B=21 and A=23
and their products will be 7×23×21=3381

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Ravi   6 years AGO

let c=x,then b=3x and a=3x+2
now a+b+c=51(given) then x=7
so a=23,b=21 and c=7 so product will be
23×21×7=3381

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Deepthi Sarvani   6 years AGO

A=B+2
B=3C
A+B+C=51
B+2+B+B/3=51
7B=147=>B=21
A=21+2=23
C=21/3=7
A*B*C=21*23*7
=3381

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abhi   6 years AGO

A=B+2 ,C=B/3 then a+b+c=51 then b=21 A=23 nd. C =7 product of A B ND C =3381

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THUMMALA VINEESHA   6 years AGO

a=b+2
b=3c
a+b+c=51
3c+2+3c+c=51
7c=49
c=7
b=21
c=23
a*b*c=21*23*7=3381

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manasa   6 years AGO

a is 2 years older than B then , A=B+2
B is thrice as C then, 3C=B then A=3C+2
sum of their age is 51
A+B+C=51
3C+2+3C+C= 51 then C=7,B=21,A=23.
then 7*21*23=3381

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Ranadip Bhattacharya   6 years AGO

A+B+C=51
A=23
B=23-2=21
C=51-(23+21)=7
A*B*C=23*21*7=3381
Hence, Option (2)

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Pragya Srivastava   6 years AGO

Let C age =x , B age = 3x , A age = 3x +2
total of their age is 51
x +3x +(3x+2)=51
so x = 7
A =3*7 + 2= 23
B= 3*7=21
C=7
Product of their age = 23*21*7 = 3381

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AMAN Sinha   6 years AGO

Acc to ques
A=B+2. eqn -1
B=3C. eqn -2
from eqn 1and 2 we got 3 eqn
A=3C+2
A+B+C=51. eqn 4
put value of eqn 2 n 3 on 4 we got the value of C i.e 7
put the value of c in 2 n 3 eqn we got value of A B C
A=23
B=21
c=7
product them n we got 3381

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vinitmendapara   6 years AGO

suppose
C's age is x
so B's age is 3x
so B's age is 3x+2

Sum of all = 51
3x+2 + 3x + x = 51
7x = 49
x = 7

A's age 23
B's age 21
C's age 7

23*21*7 = 3381

so option B

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ramakrishnateja   6 years AGO

From thegiven conditions A=B+2, B=3C, A+B+C=51.
B+2+B+(B/3)=51, 7B+6=51*3=153
7B=153-6=147 which means B=21.
A=B+2 which means A=23, c=B/3, c=21/3=7.

A*B*C=21*23*7=3381.

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Hari Priya   6 years AGO

let c be x.
so x+3x+3x+2=51
x=7
substitute and find the product. ans 3381

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Gaurang Rathod   6 years AGO

let say, Age of C is x, so Age of B would be 3x.and age of A would be 3x+2.Now Total of their age is 51 and by solving Equation we get the value of X equals to 7.Now Ages of A, B and C is 23,21,7 and product of these numbers are 3381.

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Nabendu   6 years AGO

A. x+2
B. x
C. x/3
Now x+2+x+(x/3)=51
So,x=21
So, Products of Ages are =(23*21*7)=3381

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yamini velaga   6 years AGO

let the age of `C` be `x` . Then age of `B` will be ` 3x` & the age of `A` will be ` 3x + 3`.
sum of ages = 51 ===》 x+ 3x +( 3x+2) = 51
-------> x = 7
product of ages = x. 3x. (3x+2) = 7×21×23 = 3381

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SOUMI CHAKRABORTY   6 years AGO

if age of C is x, then age of B is 3x and age of A is 3x+2.. solving that we find the individual ages and then the product

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SMRITHI V   6 years AGO

A=(B+2);B=3C=>C =B/3.
A+B+C=51
(B+2+B+B/3)=51. On Solving, A=23,B=21,C=7. 23×21×7=3381

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Jaimin Raval   6 years AGO

a is 2 years older than b also b is thrice old as c so equations a=b+2. and b=3c. sum of their ages is 51 c=c b=3c and. a=3c+2 so 7c+2=51 so c =7. and a=23 b=21 product of this is 23*21*7= 3381

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Ruchi kumari   6 years AGO

Let c=x, b=3x, a=3x+2
Given that, a+b+c=51
Then, x= 7 a=23,b=21,c=7
Product of these = 3381

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Kalidindi Sasidhar   6 years AGO

A=3C+2, B=3C, C=C
A+B+C=51---> 7C+2=51----->7C=49--->C=7,B=21,A=23
A*B*C=23*21*7=3381

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sandeep mattagunja   6 years AGO

A=(3X+2)(since a is 2 years older that b)
B=3X(since b is 3 times older than c)
C=X
now by adding
A+B+C=(3X+2)+3X+X=51(since total is 51)
7X+2=51
7X=49
X=7(result is c age)
by substituting the value of x we get
A=(3(7)+2)=23
B=3(7)=21
C=7
product of ages=23*21*7=3381

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abhishek   6 years AGO

Let C's age is x.
Then B's age is 3x .
And A's age is 3x + 2.
Therefore total age of A , B , C is 51 as per given question.
x+3x+3x+2=51
7x+2=51
x=49.

Now product of A , B , C is 7*3*7*(3*7+2)=3381
Therefore option 2)

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Ashok   6 years AGO

A+B+C=51
A=B+2
B=3C
then, A=23,B=21,C=7
23*21*7=3381

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Vaibhav Ranpara   6 years AGO

A+B+C=51.......(1)
A=B+2......(2)
B=3C.....(3)

A=3C+2
NOW PUT ALL EQUATION IN THE FORM OF C IN EQ.1
SO,
C=7
B=3(C)=21
A=B+2=23
A*B*C=21*23*7=3381

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Vuppala Sathvik   6 years AGO

A+2=B
B=3C
A+B+C=51
B-2+B+(B/3)=51
(7B/3)=49
B=21
A=23
C=7
ABC=23*21*7=3381

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Mandava saipragna   6 years AGO

a=2+b
b=3c
a+b+c=51
a+(a-2)+((a-2)/3)=51
2a+a/3=51+2+2/3
7a=53*3+2
a=161/7=23
=23*21*7

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Sarwar Shams   6 years AGO

let c be x ,b becomes 3x and A becomes 3x+2 , A+B+C=51 solving this we get x=7 -> c=7,b=21 and a=23 so product is 23x21x7=3381

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soumya   6 years AGO

let take A,B,C as 3 person.let take the age of b is x so the age of a becomes x+2 and the age of c is x/3.By solving these we get the age of A=23,B=21,C=7.

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krishameera kadalayil   6 years AGO

b+2=a
b=3c
a+b+c=51 and solving we get b=21 so a=23 c=7 and a*b*c=3381

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