A sum fetched a total simple interest of Rs. 453 at the rate of 6% p.a. in 5 years. What is the sum?

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17 Jul 2017 Simple Interest

A sum fetched a total simple interest of Rs. 453 at the rate of 6% p.a. in 5 years. What is the sum?

OPtion

1) Rs 1450
2) Rs 1475
3) Rs 1500
4) Rs 1510
5) Rs 1024
6) Rs 1660
7) Rs 1620
8) Rs 1550
9) Rs 1490
10) None of these

Solution

SI = PRT/100
P= SI*100/RT = 453*100/5*6 = 1510
Option 4)

Correct Option: 4 Best Solution (21)

jyothi chhabria   6 years AGO

SI=ptr/100
453=p×5×6/100
45300/30=p
therefore the sum is 1510 /_
option 4👍

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W J Krishna Teja   6 years AGO

Simple Interest =(P*R*T)/100
Here , SI=453
P=?
R=6
T=5
Substituting values in formula we get 453=(P*6*5)100
That gives P=(453*100)/(6*5)=1510

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Devendra Marghade   6 years AGO

Let the sum be Rs. x, then x*6*5/100 = 453
=> x=1510
Option 4)

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Ravi   6 years AGO

S.I=p×r×t/100
so,453=p×6×5/100
p=1510

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SAYAN CHATTERJEE   6 years AGO

SI.= X*6*5/100= 453
SO, sum=X= 1510
Option 4.

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ALOKENDRA PAL   6 years AGO

prt/100=453,
here r=6,t=5,need to determine p
so,p=45300/(5*6)

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AYAN PAUL   6 years AGO

We know in case of simple interest the formula is :
Interest = (P*r*t)/100
where P = Principal , r= rate of interest and t = time
So from the question if we put the values in the above equation the equation becomes
453 = (P*6*5)/100
by solving it we can get P = Rs. 1510

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G.S.Kantharao   6 years AGO

Principal=100I/RT =100*453/6*5=₹1510
Hence the Right option is 4.👈

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Pranab Thakuria   6 years AGO

SI = PRT/100
=> 453=PRT/100
=> P= (453*100)/(6*5)
=> P= 1510

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Nitish Sinha   6 years AGO

S.I =453
R=6%
T=5 yrs
Therefore ,
P=S.I*100/R*T
P=453*100/6*5
P=1510

Answer: Option 4

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santosh   6 years AGO

pqr/100=453
p=sum
q=5
r=6

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ramakrishnateja   6 years AGO

given S.I=Rs. 453/-
we know that S.I=PTR/100 which gives 453=(p*5*6)/100
(453*100)/30=p
p=1510/-

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AMAN Sinha   6 years AGO

simple interest formula is used
si=p*r*t/100
put values n find P
ans is 1510

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aribandi sridevi   6 years AGO

si=ptr/100
si=453,p=?,r=6perannum,t=5yrs
p=453*100/6*5=1510

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yamini velaga   6 years AGO

let the amount fetched be `x`
rate of interest p.a. = 6% = 0.06
amount of total interest for 5 years = 453
x × 0.06 × 5 = 453
x = 1510 rs

Like? Yes | No   

Pragya Srivastava   6 years AGO

SI =( P* R*T )/100
453= (P* 6*5)/100
P =( 453*100)/ (6*5 )
P = 1510

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mayank   6 years AGO

caluale the si of each year and then by via percentage given find value

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madanpal vishwakarma    6 years AGO

let the amount is x than as per question

453= x*6*5/100
x= (453*100)/(6*5)
x= 1510 RS

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Ranadip Bhattacharya   6 years AGO

(P*t*r)/100=453
P=453*100/5*6
P=1510
I.e., option (4)

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YAZHINI RANGARAJ   6 years AGO

s.i= pnr/100
given
s.i=453
n=5
r=6
453=(p*5*6)/100
p=(453*10)/3
p=1510

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palla anjali   6 years AGO

SI=453
Sum=p=?
rate=6%
time=5years
formula:
SI=(PTR)/100
P=(SI*100)/(R*T)
P=(453*100)/(6*5)
=1510rps

Like? Yes | No