Latest self Aptitude Question SOLUTION: Compare the numbers 0.99999... (infinitely many 9s) and 1. Which of the following statements is true? Why? 0.99999 ... < 1 0.99999 ... = 1 0.99999 ... > 1

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(#M40010034) SELF question Keep an EYE

Compare the numbers 0.99999... (infinitely many 9s) and 1. Which of the following statements is true? Why?

0.99999 ... < 1
0.99999 ... = 1
0.99999 ... > 1

jyotish r (11 years ago)

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chaitanya  (11 years ago)

well i dont know if this is correct or not, but here is my shot at it.

let 0.999999... = x
multiplying both sides by 10 we get

9.99999.... = 10x

which can again be written as

9 + x = 10x

solving for x we get

x=1.

but by first principle, it is said that

0.99999 is the closest number possible to 1 but not equal to one, because no matter how many 99999 u have, we can still find a number which has a fraction more than it.

0.99999...

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Aman  (11 years ago)

I think
0.99999 ... = 1

suppose
0.99999 ... = x
10x= 9.9999999999999
subtracting these eqns
9x= 9.0000000
x=1
so
0.99999 ... = 1

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chaitanya  (11 years ago)

0.999999....

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Sneha paliwal  (11 years ago)

ans o.9999.......... =1. because when ever infinite number is there so it is assume that it is equal to 1.

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Muhammad Ahmed  (11 years ago)

statement number 1 is right
0.99999... < 1
because 0.99999... is not complete 1, however when we round off it so it becomes 1 but after all 0.99999... is a part of 1.

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