9999 ÷ 945 = 10, remainder = 549
Hence, greatest number of four digits which is divisible by 15, 27 and 35
= 9999 - 549 = 9450
So Smallest 5 digit number divisible by 15, 27 and 35 = 9450+945 = 10395
I got placed in Infosys as well as L &T InfoTech
thanks a lot to m4maths
Rupa Muddaraboina10 Months ago
Hi friends I am attend the tcs pool campus held on mar 2nd 2016 and the results are released I am clear the written test thanks to m4 maths and give me suggestions to clear the interview round friends.
Avinash1 year ago
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