Latest self Aptitude Question SOLUTION: There are 200 numbers from 1 to 200.what is the probability of getting the number which is divisible by either 2 or 3 or 5?

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There are 200 numbers from 1 to 200.what is the probability of getting the number which is divisible by either 2 or 3 or 5?

Madhu (11 years ago)

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Vickyy  (11 years ago)

Ans: 73/100
Lets take numbers 1 to 30
numbers which are not divisible by 2,3,5 = 1,7,11,13,17,19,23,29
there are 8 numbers b/w 1 to 30.
1 to 30 is similar to 30 to 60, 60 to 90...so on
so for 1 to 180 it will be 8*6=48
from 180 to 200 its 6 numbers.
Total from 1 to 200 numbers not divisible by 2,3,5 are 54.
So from 1 to 200 numbers divisible are 200-54=146.
therefore probability is 146/200 = 73/100

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phani  (11 years ago)

numbers divisible by 2=100
3=66
5=40
0f 100 numbers divisible by 2,20 divisible by 5 and 33 divisible by 3
===>numbers divisble only by 2=47

0f other 33 numbers divisible by 3,7 divisible by 5
===>numbers divisble only by3=7

===>numbers divisible only by 5=40-7-20=13

so numbers divisible either by 2 or 3 or 5=13+7+47=67

so probabilty=67/200

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vri  (11 years ago)

18/25
206 numbers are divisible by each of 2,3 and 5.
68 are divisible by two of them
6 are divisible by all 3
venn diagram logic -> 206-68+6=144
ergo, probability=144/200=18/25

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