Latest TCS Aptitude Question SOLUTION: A and B throws dice.what is the probability that A's throws is not greater than B's throws?

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(#M40010459) TCS Numerical Ability question Keep an EYE

A and B throws dice.what is the probability that A's throws is not greater than B's throws?

Asked In TCS Madhu (11 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

PARAG KAMRA  (11 years ago)

A's throw throw could be greater than B by following ways

(2,1)
(3,2) (3,1)
(4,3) (4,2) (4,1)
(5,4) (5,3) (5,2) (5,1)
(6,5) (6,4), (6,3) (6,2), (6,1)

So in total, there are 15 possible outcomes in which the throw could exceed.

So in the probability in which A's throw can exceed is

15/36 or 5/12

Probability of failure = 1-p

= 1-15/36 = 21/36 = 7/12
probability that A's throws is not greater than B's throws=7/12(ans)

Is this solution Helpfull? Yes (52) | No (1)  

alisha kapoor  (11 years ago)

this will include the cases when A and B get the same value
so the cases possible are:
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,2) (2,3) (2,4) (2,5) (2,6)
(3,3) (3,4) (3,5) (3,6)
(4,4) (4,5) (4,6)
(5,5) (5,6)
(6,6)
so the probability is 21/36 =7/12

Is this solution Helpfull? Yes (12) | No (1)  

nandan patidar  (11 years ago)

7/12 is the right answer.

Is this solution Helpfull? Yes (2) | No   

bala bruce  (10 years ago)

A is not greater than B which means that it can be either equal or greater. so the probability can be . . . .

when A throws 1 : B can throw only 1 => 1 possibility
when A throws 2 : B can throw only 1,2 => 2 possibility
when A throws 3 : B can throw only 1,2,3 => 3 possibility
when A throws 4 : B can throw only 1,2,3,4 => 4 possibility
when A throws 5 : B can throw only 1,2,3,4,5 => 5 possibility
when A throws 6 : B can throw only 1,2,3,4,5,6 => 6 possibility
hence the required possibility is (1+2+3+4+5+6)/36(total possibility) = 7/12

Is this solution Helpfull? Yes (1) | No   

vivek chauhan  (11 years ago)

A=1,2,3,4,5
nd B=6
so prob.=(6c5.6c1)/6.6=1

Is this solution Helpfull? Yes | No (12)  

snair  (11 years ago)

ans - 7/12

not greater than => less than or equal to => 21 outcomes

probability = 21/36 = 7/12

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santu pal  (8 years ago)

answer =5/12

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Yadav Chevula  (8 years ago)

B 2 3 4 5 6

A 1 1,2 1,2,3 1,2,3,4 1,2,3,4,5

total possibilities are: 15
total probability: 1
no of throws : 36
probability = 1-(15/36)
= 7/12

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