Latest TCS Aptitude Question SOLUTION: If x^2-16>0,which of the following must be true nd how? a)-4>x>4 b)-4>x

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(#M40010643) TCS Numerical Ability question Keep an EYE

If x^2-16>0,which of the following must be true nd how?
a)-4>x>4
b)-4>x

Asked In TCS reema sharma (11 years ago)

Unsolved Read Solution (14)

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Read Solution (14) :

Ajinkya  (11 years ago)

for inequalities when you are taking square root of number remember following rules
for x^2>16
as x can be either positive or negative hence consider following cases
1] if x is positive then x > 4 (no change of inequality)
2] if x is negative then x < -4 (change of inequality)
hence -4 > x > 4 is the correct answer but on TCS openseeme they given the wrong answer

Is this solution Helpfull? Yes (32) | No (2)  

PARAG KAMRA  (11 years ago)

(a^2-b^2)=(a+b)(a-b)
X^2-16=(x+4)(x-4)
x+4=0 -->x=-4
x-4=0 -->x=4
so value of x lies between 4 and -4
so a)is right ans

Is this solution Helpfull? Yes (13) | No (16)  

Anshul Gupta  (11 years ago)

the equation will be satisfy only if
x belongs to (-infinity , -4)and (4 , infinity)
values of option A is not satisfying equation.
so the ans is option B.

Is this solution Helpfull? Yes (12) | No (8)  

ASWARTHA  (11 years ago)

x2-16>0
x2>16
then x>-+4
hence it is lies between -4>x>4

Is this solution Helpfull? Yes (7) | No (4)  

kumara swamy D G  (11 years ago)

x^2-4^2>0
(x+4)(x-4)>0
x+4>0,x-4>0

Is this solution Helpfull? Yes (4) | No (5)  

ankit singh  (11 years ago)

x^2-16>0
x^2-4^2>0
(x-4)(x+4)>0
x>4
x>-4
so the answer is a)-4>x>4

Is this solution Helpfull? Yes (2) | No (11)  

Srivastav Reddy  (11 years ago)

its option [a] such a simple Q_ :)

Is this solution Helpfull? Yes (1) | No (17)  

ragini devi  (11 years ago)

x^2-16>0
(x-4)(x+4)>0
then the value of x is selected such that X>4 and X0
also -ve value of x say -5 then (-5)^2 -16=9>0
so x>4 and x

Is this solution Helpfull? Yes (1) | No (4)  

mini agrawal   (11 years ago)

for x= -4 ans is not > than 0 but for value less than -4 it is > than 0

Is this solution Helpfull? Yes (1) | No (5)  

Sara  (10 years ago)

The equation will satisfy for all numbers >4 and >-4. Hence the right answer will be X = >+/-4

Is this solution Helpfull? Yes (1) | No   

avinash  (10 years ago)

but is it ever possible that a number is less than -4 but greater than 4 , plz rectify me

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Basu Chadda  (9 years ago)

(x-4)(x+4)>0
so,(x-4)>0 and (x+4)>0
then
x>4 and x

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prashant  (9 years ago)

the answer must be x4

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JYOTHI BANKA  (8 years ago)

x^2-16>0
x=+-4
so x lies b/w -4and+4
so ans is -4>x>+4

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