Latest TCS Aptitude Question SOLUTION: The base address of a 2-D integer array NUMS of dimension 5*7 is 3000. What will be the address of element NUMS[3][6], if array indices start from 0 and each integer takes two byt

• Placement Papers
• /
• TCS

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40010788) TCS question Keep an EYE

The base address of a 2-D integer array NUMS of dimension 5*7 is 3000.
What will be the address of element NUMS[3][6], if array indices start from 0 and each integer takes two bytes.


a) 3056 b) 3038 c) 3054 d) 3036

Asked In TCS shyamjee kumar (11 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (5)   (0) Submit Your Solution

Read Solution (5) :

Shashank Mishra  (11 years ago)

you can follow formula's directly but for ease i write it here manual working

as indices starts from 0 so nums[3][6] means you have to access 7th element of 4th row (as i mentioned index starts from 0 ). so before access this element we have to compute 3 rows and 6 elements of 4th row hence
(3 rows * elements in row * size)+( 6 elements * size) so that
(3*7*2)+(6*2)=54 so
address of NUMS[3][6]=base+54 = 3054
answer is c)3054

Is this solution Helpfull? Yes (19) | No   

lala  (11 years ago)

sorry for the previous solution
formula is --------base address+word*(n*(i-1)+(j-1) if starting address is (1,1)but if starting address is (0,0)no need to subtract 1 from i and j
if starting address is (0,0) then formula is base address+word*(n*i+j)
here m=5,n=7,i=3,j=6,word of 2 bytes
so answer is 3000+2*(7*(3)+(6))
3000+2*27
3054
am i right...........?........:)

Is this solution Helpfull? Yes (5) | No   

Nithin  (11 years ago)

ans:3054
array starts from Nums[0][0]=3000;
given arrar address is Nums[3][6]=Nums[3+1][4+1]=Address =28-1=27
so ans is 3000+27*2=3054

Is this solution Helpfull? Yes (2) | No (2)  

lala  (11 years ago)

base address+word*(n*(i-1)+(j-1)
here m=5,n=7,i=3,j=6,word of 2 bytes
so answer is 3000+2*(7*(3-1)+(6-1))
3000+2*19
3038
am i right...........?........:)

Is this solution Helpfull? Yes (1) | No (9)  

harmohit  (11 years ago)

Guys i need ur help...The problem is that i do not know from where should i prepare for TCS...I have gone thru open Sesame and i know the pattern..But prob ye hai ki previous year kaha se krun based upon the latest pattern..Help me pls...

Is this solution Helpfull? Yes (1) | No   

Please Login to Read Solution.